# Calculating currents with a current source in series

Is this circuit correct? I am not sure if I can consider I5 as a current source. I remember that current sources cannot be in series.

Or is this as easy as it looks. Specifically I am getting I1=0.8232 I2=0.5488 I3 = 0.5875 I4 = 0.783 A. The confusion is caused by I5 which I believe is a current source.

• Given the schematic, I5 should not be a current source (since no current source is drawn). However, if this circuit were just a 12V source and the 4 resistors drawn, I5 would be 1.37A, not 5.0A. Looks like my calculations match yours, so I'd guess this is just a bogus schematic/problem. – Shamtam Nov 26 '13 at 3:30
• If 5A is flowing as shown then you need to consider it part of the question if you are going to attempt to answer it (which you have done) OR give a decent argument why the 5A should not be considered part of the question and don't answer it. – Andy aka Nov 26 '13 at 8:28
• Well using nodal analysis by taking junctions A and B across I 5 gives a system of equations with no solutions. Specifically (0-Va)/6 + (0-Va)/9 = 5, 5 = (Vb-12)/12 + (Vb-12)/9, Va = Vb. – Dimo Nov 26 '13 at 14:20