2
\$\begingroup\$

I have to analyze an amplifier circuit for 8 ohms, 0.025 watts speaker and don't understand how it works. What is the working principle of the components? What configurations are used? In which stage does the amplification take place? What biasing are used and why?

enter image description here

\$\endgroup\$
5
  • \$\begingroup\$ The configurations are all common emitter. In the last one, the speaker serves as the load, so the stage basically drives current through it. Amplification takes place in all the stages. Resistors R5 and R3 are quite pointless without emitter resistors on Q1 and Q3. R4 provides global negative feedback, C2 is "dominant pole compensation". \$\endgroup\$
    – Kaz
    Dec 6, 2013 at 3:47
  • \$\begingroup\$ Did you mean to say 25 watts in the title or just 0.25 watts? \$\endgroup\$
    – Andy aka
    Dec 6, 2013 at 11:56
  • \$\begingroup\$ or 0.025W @Andyaka ;o) \$\endgroup\$
    – jippie
    Dec 6, 2013 at 13:23
  • \$\begingroup\$ just 0.025 watts. \$\endgroup\$
    – Kaiju19
    Dec 6, 2013 at 13:37
  • \$\begingroup\$ Can someone please explain to me, why is that there is a resistor after c1? \$\endgroup\$
    – Kaiju19
    Dec 6, 2013 at 13:40

1 Answer 1

1
\$\begingroup\$

Can someone please explain to me, why is that there is a resistor after c1?

With this amplifier topology the global gain is defined by \$A=\dfrac{R4}{R1}\$, provided that the open loop gain from the transistors is much higher than that.

In that the base of Q1 will act as virtual ground for the AC signal. Notice that for DC the base is biased to approximately 0.6V. With R1 at (virtual AC) ground, your input impedance equals R1.

A simplified opamp circuit would look like this (notice that it will not work in practice due to low voltage).

schematic

simulate this circuit – Schematic created using CircuitLab

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.