Well I finally obtained another multimeter, so now I have a Mastech MS8226T and a Ben Electronic M92A. I decided to measure at which voltages would the low battery warning appear and how much current each of them consumes.

So here's my setup: Power supply->M92A->9V plug->MS8226T->other end of the 9V plug->power supply.

I used M92A to measure current and wanted to use MS8226T to measure voltage. Unfortunately, I couldn't measure the supply's voltage using MS8226T. I always got 0 V. When I swithched the meters, M92A would show voltage out of range for every scale.

So I decided to use the powered on meter to measure current and the second meter to measure voltage. I got zero as result on both meters, when I wanted to use them to measure their own curent consumption.

Why is that so?

EDIT Here are the schematics.
first image On this image, XMM1 is the meter measuring current and it is powered by its battery. Meter XMM2 is powered by the power supply V1. I used R1 as the meter's power plug. When I use MS8226T as XMM2 in such a set-up, I get zero volts on the supply. When I use the M92A, I get out of range on all ranges. The XMM1 meter shows expected values.

second image On this image meter XMM1 is powered by its internal battery, is measuring voltage and shows expected values. Meter XMM2 is measuring current and reads zero. I'm using resistor R1 instead of meter's power plug here.


1 Answer 1


It's because of the circuit used inside of the multimeter to create a virtual ground at approximately Vbat - 6.2V, or about 2.8V for a 9V battery; this basically means the COM terminal on the meter is at 2.8V relative to battery ground and readings will be offset by this.

I tried with another meter to measure its 9V battery - it read 6.08V, which is very close to the predicted 2.8V drop.

  • 1
    \$\begingroup\$ So, if I understand what you wrote corectly, the potential of the com port is potential of the - side of the battery plus 2.8 V. Now, if I connect the power supply as the meter's power source, the supply's - side is meter's - side. Since the voltge between ends of the power supply is around 9 volts, and the voltage between the com port and the - of the supply is 2.8 volts, I should be getting around 6.2 volts reading for supply's voltage, since the reference point is same for both com and supply voltage. I get zero at one meter and out of range for all scales on the second meter. \$\endgroup\$
    – AndrejaKo
    Commented Feb 1, 2011 at 19:10
  • \$\begingroup\$ Also, while this would make an impact on voltage measurement, why would it afect current measurement? \$\endgroup\$
    – AndrejaKo
    Commented Feb 1, 2011 at 19:11
  • \$\begingroup\$ @AndrejaKo, it would affect current measurement as that is just measuring a voltage dropped across a shunt resistor. \$\endgroup\$
    – Thomas O
    Commented Feb 1, 2011 at 19:22
  • \$\begingroup\$ @AndrejaKo, am I understanding you correctly that you cannot measure the voltage across a power supply? It would be helpful to see a schematic/diagram as I am confused by your description. \$\endgroup\$
    – Thomas O
    Commented Feb 1, 2011 at 19:24
  • \$\begingroup\$ @Thomas O OK. But that still doesn't explain zero reading on both meters. Since the reference is 2.8V, I'd expect current readings to be decreased proportionally. \$\endgroup\$
    – AndrejaKo
    Commented Feb 1, 2011 at 19:24

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