I'm given this circuit which is in steady state:
At some point the switch closes. What happens to the voltage across the inductor and the current through it?
Well, the way I see it is that if the circuit reached steady state, the inductor is a short so adding a resistor in parallel with it does nothing as no current will run though the resistor which means no voltage will build up at the junction between the inductor and two resistor. The voltage across the inductor is 0V and the current through it is 20/10k = 2mA no matter when I check after reaching steady state.