# Questions tagged [stability]

The ability of an electrical circuit to stop oscillating within a finite period of time. Related topics include the Nyquist stability criterion (and the associated Nyquist plot), Bode plots, and gain and phase margin.

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### Why will an ideal double integrator oscillator only oscillate at one frequency?

I am trying to learn about RF oscillators. Example 8.6 in the oscillator chapterof RF Microelectronics 2nd edition by Razavi asks to solve for the frequency and amplitude of the oscillation of an ...
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### Selecting the compensation components, RCOMP and CCOMP, in a DC-DC converter

We know that in that selecting the compensation components, RCOMP and CCOMP, a DC-DC converter like the LM5155 is crucial for setting the control loop bandwidth and ensuring stable operation. These ...
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### Repeated poles at origin: does this make system unstable, and why?

Let's say we have a control system that ends up having two poles at the origin. I've simulated this and it appears as though this takes the system into instability. I just wanted to confirm, does ...
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### Sizing the output capacitor of DC-DC convertor

My questions is continuation of my previous post: Adding capacitors to the power stage of a DC-DC convertor (SEPIC&CUK) My fist question is which capacitor in the circuit should be considered as ...
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### Adding capacitors to the power stage of a DC-DC convertor (SEPIC&CUK)

I'm working on the following reference design form TI: Based on the test report it can provide 50 mA to each rail and +60 V/-60 V. In my application there will be pulse current draw from this circuit ...
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### How is this ADC voltage reference buffer not unstable?

See attached images. They show an ADC voltage reference buffer with 22uF of output capacitance, a graph of the OPA350 stability with capacitive load and isolation resistance, and an ADI document about ...
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### Is a type-2 system always unstable?

If there are multiple poles at the origin, a system is unstable. A type-2 system will be have $s^2$ in the denominator. So it should be unstable, right?