I am looking at using two p-ch MOSFETs in series as part of a high-side load switching scheme, and do not understand the following circuit behaviour.

In simulation of the simplified schematic below, no current is driven into the load: 

[![enter image description here][1]][1]

*Edit: The MOSFETs being modelled are DMP2008UFG, [model supplied by manufacturer ][2]*

If neither Q1 or Q2 are conducting, Q2 has a floating source voltage and therefore undefined Vgs.

What I expected to happen:

 - Q1 to turn on, as its Vgs > Vth.
 - As Q1 is on, then Q2's source if no longer floating and is instead defined at near Vcc.
 - As Q2's Vgs>Vcc, Q2 conducts
 - Current flows into the load

Clearly I am misunderstanding the circuit. Why does no current flow into the load?

Many thanks in advance,

Gerry


  [1]: https://i.sstatic.net/lQP9f.png
  [2]: https://www.diodes.com/products/discrete/mosfets/mosfet-master-table/p-channel/p-channel-8v-to-29v/part/DMP2008UFG#tab-details