I have the following circuit as shown in the picture.My question is how can I perform Node analysis in this circuit in the node \$V_{0}\$? 

I want to find \$i_{1}\$ but without KCL or KVL.Just the node analysis in the node \$V_{0}\$.

I tried :
\$\frac{V_{0}}{6} +\frac{V_{0}}{4}-1 = 0  \$ ignoring the ccvs.If I take it into account the dependent ccvs how the node analysis will be ? 

Any help ? 

(Side note: I know that KCL in node \$V_{0}\$ and KVL in the left sub circuit solves it but I want to see the node analysis how will be changed if I take into account the dependent source. The current source 1A is the circuit excitation in the terminal A,B)

[![enter image description here][1]][1]


  [1]: https://i.sstatic.net/9oEYy.jpg