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It's got an analogue input which you can use to measure the current, and digital I/O pins which can be used to cut the power, and provide a reset input. … Only cut the power if the current draw is more than 500mA for 2 seconds. Whatever you want. …

Why can't the FET do its own current limiting? Isn't a FET basically a voltage to current converter? … Instead of providing 5v (or whatever) to the gate to switch it on, could you use a resistor divider to provide about 3.8v which will automatically limit the current to about 300mA. …

I want to control the current in a solenoid using a microcontroller. Ideally, I would an IC which can do PWM with per-cycle current limiting, with an SPI input. … I've also looked at LED drivers, which have the right kind of drive, but do not allow the current to be controlled by an MCU. Does anyone know of such a device? …

The OP wants to create a 5A current pulse for 100us. They want to have a current rise time of 1us at the start of the pulse. This is obviously 5MA/s. …

The reason it droops is that you don't have enough current from those high value resistors to charge the internal capacitor during the short sampler period. …

I would like to do this with a fairly smooth current through each LED. I.E. … What other ways are there to achieve smooth current control through LEDs? Are there any chipsets which do this? …

You'll notice that there's no current limiting resistor. The current limiting will be performed dangerous open-loop style by the MCU. … Here is a circuit which is a linear current regulator. …

If only there was a component which conducted high speed signals, but blocked DC current. Oh wait, there is. It's a capacitor! … The return current will flow along one plane, then, when the signal track changes layer, the return current will come up one via, through the capacitor, down the other via, into the other plane, and continue …

This will hold the output voltage at the peak current value. Just add a capacitor in parallel with RL. …

Have you tried using a normal recharegable AAA battey? They're only 1.2v, but they have a lower internal resistance, so it might make up the difference. It's worth a try.

The current flowing in: the bottom resistor must therefore be 10v/1k = 10mA. the right resistor must be 0mA, because it has the same voltage on both sides. the two resistors in the top half form a potential …