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If you apply a lowpass filter to the measured voltage, the result will be averaged, and it will be proportional to duty cycle. If you then use a microcontroller SAR ADC to acquire it, since there will …

Do you know where does the transient come from? I don't see what you call a "transient". Did I choose the right transistor to achieve what I want? Since you tell nothing about intended load …

Adding a little bit to the other answers... If your motor draws 2A nominal, then it will draw a lot more when stuck/stalled/starting. It would not be unreasonable to expect 10A in a stall. Brushed DC …

Q1 and Q2 are wired in reverse. They're PMOS. The optos are useless, simple NPN transistors would work. Also, your optocouplers will introduce a delay which will cause both FETs to conduct at the sa …

The chip has internal MOSFETs with body diodes that will act as rectifiers, so when the motor acts as generator, or produces back-EMF, the energy will be sent into the power supply. Protection measure …

Am I using too many components for an Engine like this? No, if you want to change direction you need a H-bridge. Is This 10k Necessary for P Channel? Can't say without reading driver datasheet. I …

If the 24V is really 24V, and not automotive 24V than can get a lot higher, I'd use a pair of cheap half-bridge MOSFET drivers with integrated adaptive dead time like NCP5901, ADP3120, ADP3110, etc. I …

Notice the fine print on DMP3056 datasheet about how RthJA of 91°C/W is measured... Note 5: Device mounted on FR-4 substrate PC board, 2oz copper, with thermal vias to bottom layer 1inch square coppe …

I don't want to make this a one-link answer, so I'll write a quick summary, but you should really read this appnote. If I use the equation Q=CV I can find the charge Not really. MOSFET capacitan …

I ran a quick simulation... X1 is a Darlington transistor used as follower, so its Vce will be 2*Vbe plus voltage drop in R1, so about 1.5V. With 400mA through the load it dissipates 0.6W. With the i …

Capacitor: 40uF, DC Power Source: 100V, DC Switching time: ~us (originally nanoseconds) Current in a capacitor can be calculated from the derivative vs time of voltage across it: \$ i = C dv/dt \$ W …

boost converter which will boost the 12V to 120V, Transformer will be much more efficient and cheaper than boost converter for that high output/input voltage ratio. Say you need 120V 10A, if it is 1 …

Three problems: 1N4004 is rated to 1A, not 20A. And it is too slow. You can use the FET body diodes instead. They should not conduct often if the FETs are driven synchronously, so there should be no …

On your layout the decoupling cap (finger-painted red) is very far away from the chip, there is a 5R resistor in series (purple) and the current loop area (highlighted in yellow) is quite large. Th …

Datasheet says: "Effective Output Capacitance, Energy Related" = 15pF Coss (Cds+Cgd) capacitance is charged from the power supply every time the FET turns off, which stores some energy. When the FET t …