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In this video, the instructor claims current will be 90 degrees behind voltage inside the capacitor but not inside the resistor or the whole circuit. If that's true, I don't understand. … I am imagining current as a flow of water inside a tube and I cannot see how the water can be delayed on a point in the tube and not delayed 1 inch later. Can someone please explain? …

I am trying to calculate the voltage between A and E by using Kirchhoff current law. This is what I did. … I assumed that this current was clockwise, so \$ I_{2} = -2 A \$ right? …

, on a critically damped RLC circuit current will oscillate and be like this \$ I_{\infty} \$ will be an equation, not a value, right? … What is the the meaning of this \$ I_{\infty} \$ on the current equation and how do I find it? …

I am trying to do a nodal analysis of this circuit. and I need to do this by nodal analysis only. I need to find \$ i_1 \$, \$ i_2 \$ and \$ i_3 \$. I have found that \$ i_1 = \frac{V_B - V_A}{R …

I mean a difference in potential between terminals of a current source? … If all this is true, the current source is the one driving the circuit, R1 and the voltage source V1 are not having any effect. No current circulating from V1/R1. Is this calculation wrong? …

Some authors say that electrons move from negative to positive and current from positive from negative. … Charges, electrons and current? Is the effect similar to a newton cradle, where one ball knocks the first one and the force is transmitted through the chain? …

Current tries to reach the capacitor but the inductor is preventing it. Magnetic field is building in the inductor. Current is increasing and its Voltage is dropping. … Current finally reaches the capacitor. It starts charging. Its voltage starts to rise. Capacitor is building electric field. …

initial conditions: voltage at t=0 (I would solve the equation for t=0) dv/dt at t=0 (I would derivate the equation and solve for t=0) Now suppose that I want to do the particular conditions for the current … I suppose the conditions are the same, so, if I have the current equation, I have to integrate that to get voltage's but doing so, I will generate a constant of integration that will be a third unknown …

The first condition is current when t=0. We know that the inductor will resist the initial current, so i(0) = 0. … We know that current will be zero, because the inductor will guarantee that, so \$ \frac{di}{dt} = \frac{V}{L} = 0 \$ so, \$ i(t) = (At + B)e^{-\alpha t} \$ \$ \frac{di}{dt} = 0 = -\alpha A t e^{- …

I am reading this doc I see this magic happening on the third line of equations... How in the name of Math, does this \$ Ae^{st} \$ appeared there? Magic?

I have removed the load and calculated the norton current to be -2A. Now I try to calculate the norton resistance. … Without the load, I short circuit the voltage source and remove the current source. I end with this!!! what??? the circuit is interrupted. …

Hfe is 225 for that current. Resistors are calculated to have Vbe = 0.7V and Vc = 4.5V. I am trying to understand what happens when I inject an AC signal at the base. … Base current is now less than before, because the difference in potential across base resistor is less than before. If base current is less, collector current is less, right? …