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It is not a quartz oscillator, it is a quartz crystal, which needs to be connected to an oscillator circuit to make a clock signal. …

You need to estimate or measure the additional capacitances to know what the actual load on the oscillator is. … Like I said in the previous point, there are other capacitances loading the oscillator output as well, not just the chip input capacitance. …

Crystal oscillator waveforms at the crystal pins are sinusoidal. Expecting square waves is wrong. …

Simplest is a CMOS ring oscillator. You only need a CMOS IC with three (or five, or any odd number of) inverters connected in a ring. … 74HCU04, because buffered inverters like the 74HC04 already have three CMOS inverters per single inverter gate, so in that case a buffered inverter gate could simply be connected by itself as a 3 inverter oscillator …

Yes, correct Maybe, it is hard to prove but it is likely that no part of your wiring or probing allow for a 50 MHz square wave oscillator to work properly and be probed properly. … The oscillator can't get power quick enough to do 50 MHz square wave, the wiring inductance prevents it. Third problem is the probe connection. …

25 ppm is better. 25 ppm is half of 50 ppm. But there are some caveats. A single value tells only half the truth. Oscillators have both initial tolerance of some ppm, and temperature stability of some …

That is a series resonant oscillator circuit, so you need a series type crystal which runs at the given frequency in series operation. …

The circuit must have some other path for the connection. For example circuit power supply can be connected to PC ground via grounded mains plug, and the PC oscilloscope ground is connected to PC gro …

Rext calculation looks correct. However the capacitor calculations should take stray and pin capacitances into account as well, so in reality you need smaller capacitors, maybe 10pF. In some STM32 doc …

The datasheet says Cs which includes pin and PCB wiring capacitance can roughly be approximated as 10 pF. Therefore when a 6pF load is needed, you need 12pF of capacitance, and subtract 10pF stray, an …

What is important to remember that even if the oscillator is only 2 MHz, it will generate edges at 4 MHz and ideal edges have in theory frequencies up to infinity. … It will help with EMC compliance and makes less noise on the oscillator supply voltage as lower gulps of current is needed each edge. …

This seems like a mixture of incompatible oscillator circuits. … It might be a good circuit, but in practice, a Pierce oscillator should be relatively simple to get working. …

The reason is hysteresis. It keeps the output in a stable state until input voltage crosses the threshold voltage to toggle output state. It should not work with a standard inverter.

You seem to have the 25 MHz HSE crystal on the LSE oscillator pins. Not seen in schematics, but the assumption is that your 32768 Hz LSE crystal is on the HSE oscillator pins. …

Each different type of logic needs different external component values. 74LS should be possible but it may require completely different oscillator topology with two LS inverters and very low value resistors …