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A resistor obeys Ohm's law (\$\small V=I\cdot R\$); the current through it is equal to the voltage across it divided by the resistance (equivalently \$I=\frac{V}{R}\$).
7
votes
Is negative resistance possible?
My apologies to everyone, the original solution was wrong, I had the direction of the currents through R2 and R3 reversed. Solution now edited.
If we Measure all voltages relative to the common jun …
5
votes
Accepted
Compute voltages and equivalent resistance in the presence of a bridge
I've just checked the first half of the problem by transforming the delta R3, R4, R5 to a star and get the equivalent resistance to be 44.8 ohms. Which agrees with your first set of calculations. Ther …
0
votes
How to compute resistors values in bipolar transistor circuit?
As I can see when the button is closed the base of Q3 will be at ground so Q3 is switched off and no current flows. D3 and D4 are off and the emitter of Q3 is also at ground. Consequently the base of …
5
votes
Accepted
Charging capacitor with a diode in parallel
Initially you can ignore the diode, but once the voltage across the resistor and the capacitor reaches the forward voltage drop of the diode, Vf, it will be effectively clamped and all the current wil …
0
votes
Is this a series or parallel circuit? Why?
As far as I can see they are in series. They have a single point in common, the junction of the LED and the resistor and the same current flows from the Arduino, through each in turn and back to groun …
2
votes
What happens when a already charged capacitor is connected to a power supply with less volta...
You show the power supply as a battery. Most batteries, both primary and secondary, can absorb current in the reverse direction. The capacitor will discharge into the battery, the rate depending on th …