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A resistor obeys Ohm's law (\$\small V=I\cdot R\$); the current through it is equal to the voltage across it divided by the resistance (equivalently \$I=\frac{V}{R}\$).
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Why is the right half of the circuit irrelevant?
A follow-up this post regarding the following circtuit:
I continue to struggle to understand why the right half of the circuit is irrelevant when computing the voltage between \$A\$ and \$B\$. One a …
8
votes
6
answers
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Not understanding why these two resistors are in parallel
We are asked to simplify the following circuit:
simulate this circuit – Schematic created using CircuitLab
I argue as follows, in order upper-left, upper-right, lower-left, lower-right:
simulate …
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0
answers
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Two reasonings reach the same solution, yet one must be wrong [duplicate]
Another follow-up to this post, regarding this circuit:
Above \$V_1\$ applies a rectangular wave of amplitude \$24\ \mathrm{V}\$. For this post I'm only concerned in the case \$V_1 = -24\ \mathrm{V}\ …
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Stuck in a Thévenin's Theorem exercise
I'm practicing applying Thévenin's Theorem, and I'm struggling with computing \$R_{th}\$ in the following circuit:
My attempt: after removing voltage and current sources, and combining resistors in series … Can I treat \$R_1+R_2\$ and \$R_4\$ as resistors in series? The fact that node \$A\$ lies between them makes me unsure. …
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Rigorous Definition of Resistors in Parallel when Circuit is Defined as a Graph
Given the definition of a circuit as a graph, would the following be a correct definition of two resistors \$R_1\$ and \$R_2\$ being in parallel? … of the edges in \$p\$ or \$q\$ are voltage sources, resistors, inductors, or capacitors. …