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A resistor obeys Ohm's law (\$\small V=I\cdot R\$); the current through it is equal to the voltage across it divided by the resistance (equivalently \$I=\frac{V}{R}\$).

0 votes
2 answers
175 views

Why is the right half of the circuit irrelevant?

A follow-up this post regarding the following circtuit: I continue to struggle to understand why the right half of the circuit is irrelevant when computing the voltage between \$A\$ and \$B\$. One a …
Sam's user avatar
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8 votes
6 answers
6k views

Not understanding why these two resistors are in parallel

We are asked to simplify the following circuit: simulate this circuit – Schematic created using CircuitLab I argue as follows, in order upper-left, upper-right, lower-left, lower-right: simulate …
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  • 227
0 votes
0 answers
30 views

Two reasonings reach the same solution, yet one must be wrong [duplicate]

Another follow-up to this post, regarding this circuit: Above \$V_1\$ applies a rectangular wave of amplitude \$24\ \mathrm{V}\$. For this post I'm only concerned in the case \$V_1 = -24\ \mathrm{V}\ …
Sam's user avatar
  • 227
1 vote
0 answers
92 views

Stuck in a Thévenin's Theorem exercise

I'm practicing applying Thévenin's Theorem, and I'm struggling with computing \$R_{th}\$ in the following circuit: My attempt: after removing voltage and current sources, and combining resistors in series … Can I treat \$R_1+R_2\$ and \$R_4\$ as resistors in series? The fact that node \$A\$ lies between them makes me unsure. …
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0 votes
0 answers
71 views

Rigorous Definition of Resistors in Parallel when Circuit is Defined as a Graph

Given the definition of a circuit as a graph, would the following be a correct definition of two resistors \$R_1\$ and \$R_2\$ being in parallel? … of the edges in \$p\$ or \$q\$ are voltage sources, resistors, inductors, or capacitors. …
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