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mechanically-adjustable special-type variable resistor with 3 legs and it is used as a potential-divider. (It is not a meter at-all, but got the name from its historical ancestor which was a meter.)

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Adjust the potentiometer to get the desired collector current, then record the other values as required. If you don't understand the assignment, you should ask your instructor, lab assistants, or other students. …
answered Oct 2 '15 by Peter Bennett
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The current in the circuit will be determined by the total resistance in the circuit. If the potentiometer is set to 1000 ohms, the total resistance will be 1100 ohms, so, with a 4 volt power supply …
answered Mar 18 '16 by Peter Bennett
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You should study the circuit around the pot you intend to replace to see what effect, if any, changing the value of the pot would have. If the pot is connected as a voltage divider between Vcc and gr …
answered Apr 18 '16 by Peter Bennett
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The usual way to connect a potentiometer as a volume control is: simulate this circuit – Schematic created using CircuitLab That will make the output vary from 0% to 100% as you turn the knob …
answered May 21 '17 by Peter Bennett
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Looking at the Electrical Characteristics of the LM2901, I see that the common-mode input voltage range is 0 to Vcc-1.5 volts. You have the negative inputs at 4 volts, or Vcc-1, which is outside the …
answered Aug 18 by Peter Bennett
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When measuring resistance under a few ohms, you must allow for the resistance of your meter leads and connection to the device you are measuring. Many meters will read 0.5 ohms or so with the leads s …
answered May 5 '15 by Peter Bennett
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Yes, you can use a pot to provide a variable input to the ADC. Connect one end of the pot to +3.3V, the other end to Ground, and the wiper to the input of the ADC. As you turn the pot, the voltage a …
answered Dec 9 '17 by Peter Bennett
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From one of your comments, it seems that all you need is a DPDT (double pole, double throw) pushbutton. One pole would be used to apply power to the solenoid valve, and the other pole would switch th …
answered Dec 25 '15 by Peter Bennett
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In a series circuit like this, the voltage across each resistor is proportional to its resistance, so you can solve it simply by looking at the voltages across each resistor, and the given value of on …
answered Mar 31 '15 by Peter Bennett
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resistance of your potentiometer is much less than that. With the pot and meter in series across the power supply, they form a votlage divider, and almost all of the supply voltage will be dropped across the meter, due to its very high resistance relative to the potentiometer. …
answered Jan 5 '17 by Peter Bennett
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I expect that the terminal you marked "2" is the wiper (moving contact), and "3" is the top (ungrounded, input) terminal. If you want maximum gain with the pot removed, jumper "2" to "3".
answered Nov 20 '17 by Peter Bennett
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A volume control is generally wired as a voltage divider, like so: simulate this circuit – Schematic created using CircuitLab It is hard to say how this should be done in your situation, witho …
answered Jul 15 '18 by Peter Bennett
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A potentiometer is just a resistor - current can flow through it in any direction (including from/to both ends to/from the wiper). If you are just using it as a single variable resistor, rather …
answered Nov 4 '18 by Peter Bennett
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I see five holes for connections to the pot. There is one hole in the center of the pot drawing on the PCB - that hole is for the wiper of the pot, and should be connected to the center terminal of t …
answered Dec 8 '14 by Peter Bennett
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Figure 2. Switchable polarity version. Note that while the batteries, switches and potentiometer have a maximum of 18 V across them they are possibly all at high voltage (1,000 to 4,000 V) with respect … to ground and you. All need to be properly insulated. The metal case of the potentiometer should not be grounded (as you're unlikely to find one with a 4,000 V rating between the carbon track and the …
answered Feb 2 '16 by Peter Bennett

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