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The transistor is a semiconductor device that can amplify signals and switch power. Most used types are bipolar (BJT, for Bipolar Junction Transistor), UJT (Unijunction transistor) and MOSFET (FET, for Field Effect Transistor)

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Part of an answer: If it [#ON Input] is driven high while the external MOSFET is turned on, GATE is pulled low with a weak pull-down current (40μA) to turn off the external MOSFET gradually. …
answered Mar 26 by Huisman
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You could replace all BJT's by n-channel mosfets, then you don't need to invert the driving signals. However, the Law of Conservation of Misery will apply: you now need to level shift the signals for …
answered Jun 29 by Huisman
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Because often, the exact voltage isn't known. When the input signal is LOW, you're right could be any value between 0V and some other maximum upper value. It is either defined in the component's da …
answered Jun 20 by Huisman
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1) This is the power schottky rectifier STPS5L60S from ST 2) mattman944 gave an excellent comparison With regards to repairing: Be sure you not only fix the result of the problem (replacing the br …
answered Jul 6 by Huisman
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Use a normally closed relay. Reasons: The relay is isolated, just like the optocoupler The shown circuit will only work when the (voltage) potential of "NC Terminal A" is higher than the (voltage) p …
answered Aug 7 by Huisman
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The problem is the comparator has to have a supply voltage for all cases. So, V1 as well as Vbatt have to be connected to pin 7. You should use ORing diodes for this. The reason that the comparator g …
answered Aug 30 by Huisman
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Why does this driver not have a load resistor? Because it is not needed. When a motor starts, for a short time there will be a starting current / inrush current / stall current. When a motor is …
answered Aug 7 by Huisman
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cascade), and using various mixtures of NPN and PNP transistors. There are many combinations, and it is hard to provide the detailed analysis that each deserves in a short article. Instead, I … will show some of the common variations, purely for interest's sake. If you want to know more, you will need to perform your own analysis because the choice of transistors determines how well each …
answered Jul 10 by Huisman
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You were almost there! You can indeed use a PMOS keeping in mind the ratings (regarding VDS and IDS). It should be oriented like you drew it: the body diode is reversed biased. To turn on the PMOS, y …
answered Jul 5 by Huisman
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The problem with PNP circuit is that the Raspberry Pi works on 3.3V while your Vcc is 12V. So, putting either a low signal (0V) or high signal (3.3V) always will turn on the PNP, because in both cases …
answered Jul 17 by Huisman
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Assuming signal C originates from at least a 3.3V power supply, you could use a relay that accepts a 3V3 coil voltage and drive that relay indirectly with signal C. Example: JQC-3F-03VDC Another sol …
answered yesterday by Huisman