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Often misused term, when "bit-rate" is meant.

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The UART doesn't care as long as it is reasonably exact. \$\frac{15000000}{230400}\approx65\$ \$65\cdot230400=14976000\$ So your UART is going to be too fast by a factor of \$\frac{15000}{14976}\ap …
answered Nov 20 '16 by Simon Richter