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Measurement is the assignment of numbers to objects or events. All measurements consist of three parts: magnitude, dimensions (units) and uncertainty.

9
votes
It is not a single sweep, the display is built up over many sweeps (e.g. infinite persistence mode) so you can see the average noise and jitter (amongst other things) of the signal. Usually it will be …
answered Sep 23 '11 by Oli Glaser
4
votes
Sounds not too difficult to do what you are proposing, most digital scales use 1, 2 or 4 strain gauges in a Wheatstone bridge configuration to form a load cell. This load cell will output a small diff …
answered Jul 17 '12 by Oli Glaser
3
votes
I know there is a DIY uC design that does it both ways you suggest above: Elmcie LC meter it has the unknown C (or L) as part of an oscillator for the smaller range, and for larger capacitance it ch …
answered Aug 25 '11 by Oli Glaser
3
votes
Since the pickups have both a reactive and resistive component, it's not just as simple as measuring resistance alone. The (assuming standard coil) pickups are inductive, will have some resistance and …
answered Jan 7 '12 by Oli Glaser
5
votes
I assume "as an analog signal" means on an oscilloscope as opposed to a logic analyser. For a digital signal, it is important to be able to check the signal integrity and see whether it is subject …
answered Jul 20 '12 by Oli Glaser
1
vote
I'm not quite sure exactly what you are trying to do here, but: If the input at +UB is +12VDC, then you can ignore the capacitor and just calculate the divider voltage: \$ 12V \cdot \dfrac{R19}{R18 …
answered Apr 23 '13 by Oli Glaser
1
vote
To answer the added part of your question: Yes, the sampling rate applies to logic analysers too. Obviously the signal state will be accurately represented as it can only be 0 or 1 (unlike a DSO), bu …
answered Nov 9 '11 by Oli Glaser
3
votes
If you are familiar with microcontrollers then you can use an ADC. Place the unknown resistor as one half of a voltage divider (with known precision resistor), apply known voltage and measure the outp …
answered Jan 5 '13 by Oli Glaser