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More than one of a thing, performing the same task simultaneously

1
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voltage of the divider without load. The new resistance is the parallel circuit of the old ones. U_R12 = 10V / ( 3kΩ + 7kΩ ) * 7kΩ = 7V U_R34 = 10V / ( 3kΩ + 7kΩ ) * 3kΩ = 3V R_R12 = 1 …
answered Nov 22 '14 by Kitana
2
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I can not tell if you can put two of these modules in parallel without seeing a circuit diagram. However if one module can deliver enough current for your application, you can do it with only one … to put the two cells in parallel, they will be charged up to 4.2V, no problem. They will not catch fire or explode because of over voltage. As usual there are drawbacks, in this case two. The …
answered Nov 17 '14 by Kitana