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Digital electronics treats discrete signals, unlike analog electronics that treat continuous signals. Digital logic is used to perform arithmetic operations with electric signals, and constitutes the base for building CPUs.

2
votes
Not on its own, you need some kind of memory like with a JK latch or additional input to differentiate when which output should happen. In a JK latch the previous output is preserved if both inputs a …
answered Apr 19 '17 by ratchet freak
0
votes
The simplest solution is to swap the connections of the NO and NC pins of the relay. The next option is to invert the programming logic for that pin. You can add a few constants #define RELAY_ON LO …
answered Aug 16 '18 by ratchet freak
0
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It looks like there is a glitch happening when going from state 6 to 7 where bit C goes off before bit B come on. The solution here is using a gray code counter instead of a binary one. That way only …
answered Sep 30 '17 by ratchet freak
4
votes
Because connecting 2 outputs together is bad in the general case. your schematic requires that the input signal overrides the output signal in some way, but not all the time (to be able to use it as a …
answered Jun 8 '17 by ratchet freak
2
votes
besides the microcontroller suggested by AlmostDone you can use a small EEPROM with (at least) 4 address pins and 7 data pins. You can tie any unused address pins to ground.
answered May 8 '18 by ratchet freak
5
votes
I's a multiplexer. Logically it is the same as the following circuit: simulate this circuit – Schematic created using CircuitLab
answered Nov 23 '16 by ratchet freak
0
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If the ROM has tristate outputs or all are common drain or all are common collector then you can bus the output pins together and use a decoder to enable the correct chip. Many ROMs have high impedanc …
answered Apr 11 '17 by ratchet freak
2
votes
OR the first set of outputs together, then OR the results from that. Repeat until you have a single output. Pass that single output through a Not. Or(a=in[0], b=in[1], out=out0); Or(a=in[2], b=in[3], …
answered Nov 2 '18 by ratchet freak
2
votes
Lets take a look at the karnaugh map: $$ \begin{matrix} & C\land B' & C\land B & C'\land B & C'\land B \\ A & 0 & 1 & 1 & 0 \\ A' & 1 & 1 & 0 & 0 \\ \end{matrix} $$ You can make the 3 groups in the …
answered Oct 11 '16 by ratchet freak