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BJT stands for Bipolar Junction Transistor. It is a three-terminal electronic device constructed of doped semiconductor material and may be used in amplifying or switching applications.

1 vote
Accepted

What happens when a BJT doesn't draw enough \$I_c\$ to be properly biased?

for a given \$I_B\$, reducing \$I_C\$ will reduce \$V_{CE}\$ (which is the same as \$V_o\$ in my circuit). This is the expected behavior. Although we usually express it the other way around: Incr …
  • 124k
5 votes
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Confusion regarding the Q point of a transistor

As we know the signal is supposed to apply at the base of the transistor, This is true for a common emitter or common collector stage, but for a common base stage, the signal will be applied at the …
  • 124k
5 votes

Is it possible to find \$h\$-parameters for single transistor?

Can h-parameters be found only for two port system or can we find it for single transistor also? When we specify h-parameters for a transistor, we are talking about making a two port that contain …
  • 124k
1 vote

Common base large signal transfer characteristics

Does this now mean that Vbe = -Vi? Or is it that Vbe = 0 since the base is grounded? \$V_{be} = V_b - V_e\$ So yes, in your diagram, \$V_{be}\$ is \$-V_i\$. \$V_{be}\$ is only equal to 0 if the …
  • 124k
2 votes

Why are two maximum power dissipation mentioned for this transistor?

They're limits for different operating conditions: So the first limit is when the case temperature (\$T_C\$) is held at 25 C by some means (for example with a heat sink and forced air cooling, or j …
  • 124k
3 votes

How can I find my operating point in datasheet with i-v-characteristic of bjt?

You have several choices: Estimate the performance by interpolating between values estimated from the curves provided at nearby bias points (250 and 300 uA). Measure the response of your parts on a …
  • 124k
3 votes

base impedance of a bjt amplifier

The key words are "is defined as". This is a definition. There's no proof, it was simply chosen to simplify further analysis to take the term \$v_{be}/i_b\$ and give it the shorter name of \$z_{in(bas …
  • 124k
9 votes
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Current through the reverse biased junction in transistor

So what happens in a forward-active BJT is that the forward biased base-emitter junction creates a large number of minority carriers in the base region. … I found a slide-set that gives a very quick explanation of BJT operation here. …
  • 124k
4 votes
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Difference between CML and ECL

THis is an ECL circuit. Notice the output is from the emitters of two BJTs: (source: Wikimedia) This is a CML circuit: (source: Wikimedia) Notice the outputs are from the collectors of two BJT …
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2 votes
Accepted

Bipolar Transistor's Input Resistance

Or they actually just add the resistances without caring about the dependent source for some other reason? The \$g_m\$ source produces current in the C-E branch, not in the B-E branch. So it does …
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1 vote
Accepted

BJT Collector current

It flows through R2 and then in to the BJT collector and into the load (R). which Ic do we use - Ic in or Ic out? …
  • 124k
1 vote

How calculate and chose the right BJT that comands a relay

To maintain your 5 mA base current limit you might need to either use a Darlington configuration, or change from a BJT to a logic-level MOSFET. …
  • 124k
3 votes
Accepted

What's the differences of these usage of PNP, NPN transistors?

When operating in saturated mode, the power consumption of the BJT can be substantially lower than when in active mode. … This leads to less self-heating of the BJT, and probably a longer operating life. Note my use of "may" and "can". …
  • 124k
1 vote
Accepted

How can we prove that collector current in active region is higher than the saturation region?

In this case, the collector current is minimum at saturation, or anyway less than it was when we were operating the BJT forward-active. … In either case, saturation happens because the source (VCC and RC) isn't able to provide enough current to keep the BJT operating forward active. …
  • 124k
2 votes

Differential and Multistage Amplifiers(BJT)

The current through RE is $$I(R_E) =\frac{V(v_{o2}) - V_{BE}}{R_E}$$ The current into the base of Q3 is $$\frac{I(R_E)}{\beta+1}.$$ But this still depends on \$V(v_{o2})\$, and \$V_{BE}\$ depends n …
  • 124k

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