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mechanically-adjustable special-type variable resistor with 3 legs and it is used as a potential-divider. (It is not a meter at-all, but got the name from its historical ancestor which was a meter.)

0
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You've nearly got it. The part you are missing is that in a good design the input impedance (or resistance, if you like) will be much higher than that of the potentiometer. The result is that most of … the current flows through the potentiometer and the amplifier just "listens-in" on the potentiometer. The effect is that the amplifier lightly-loads the potentiometer. If the amplifier impedance is …
answered Jun 12 '16 by Transistor
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that the same effect as the original potentiometer can be obtained with a linear pot but the wiper position to achieve the effect won't be the same and the musically useful span might be only a few … articles that suggest that you can make your own S-curve with a linear pot and a couple of resistors between the ends and the wiper. That will, I think, generate an inverse S-curve. Figure 2. Various potentiometer curves. Source: sengpielaudio.com. …
answered Aug 12 '18 by Transistor
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potentiometer into an analog input and control the output duty cycle with that instead. You may need a transistor to switch the relay but that's about it. …
answered Apr 22 by Transistor
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circuit. In the modified circuit the voltage across D2 + R1 varies with the potentiometer and so the current through D2 does as well. As the pot is turned down D2 will dim to the point where it turns …
answered Dec 12 '15 by Transistor
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through the wiper will be limited only by the battery's internal resistance and the wiper contact resistance. Most likely this current will be high enough to destroy the potentiometer. If you edit your …
answered Feb 26 by Transistor
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white LEDs but check the datasheet values too. Your calculations: V=IxR V=Ix(R1+R2) R2 is the potentiometer R2=(IxR1)/V R2=(0.018x500)/9 R2= 1 Ohm You have a mistake on line 3. V = IR1 …
answered Oct 14 '17 by Transistor
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No that's not the problem. Putting the wrong potentiometer in will just have the effect that most of the control seems to be over a restricted angle of the pot with very little change occurring over …
answered Aug 28 '16 by Transistor
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controls are almost always configured as potential dividers so we don't do infinite resistance - instead we move the wiper to the grounded end of the potentiometer to give zero output. The infinite …
answered Jul 9 '16 by Transistor
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Can I reverse the wiring on a reverse log pot to convert it to a log/audio pot taper ... if I reverse the wiring? Yes. It will work in reverse rotation. e.g., Turn knob clockwise to turn the volu …
answered Sep 18 '16 by Transistor
2
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directly grounded on this board. For a standard volume control it would be most unusual to have resistors or capacitors in the ground leg of the potentiometer. This makes me suspect that R+ and L+ are …
answered Apr 29 '18 by Transistor
7
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I'm using 0.2W, 500ohm potentiometer ... But according to calculation, max current of this potentiometer is about 20mA. $$ I_{MAX} = \sqrt {\frac {P}{R}} = \sqrt {\frac {0.2}{500}} = 20~mA … $$ Your calculation is correct. You need to remember that this is the maximum current that can run through any portion of the potentiometer track. A common mistake is to think that if the pot was turned …
answered Jul 27 '16 by Transistor
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simulate this circuit – Schematic created using CircuitLab Figure 1. The equivalent circuit. You have 15 x 4k7 pots in parallel with the one you are testing.That means that there is a resistan …
answered Feb 2 by Transistor
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If they're available they'll be difficult to find. I suggest that you do some reverse engineering on a working unit. Record the voltages on each tab at 45° increments of the shaft. Angle | Tab 1 | Ta …
answered Mar 29 by Transistor
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Can you tell from the PCB if the device is used as a variable resistor or a potentiometer? simulate this circuit – Schematic created using CircuitLab If it's a variable resistor as shown … test pot you may need to use a higher value. For the potentiometer you're in a little more difficulty. You may have to try a few values. You can use standard pots and when you find the right value buy the correct part. …
answered Oct 26 '15 by Transistor
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For a nominal 5 V supply R6 and R7 provide a nominal 4 V volt input to the inverting inputs. This voltage will vary with the supply voltage. R1 provides an unusual means of adjusting the threshold vo …
answered Aug 18 by Transistor

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