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A fundamental electronic component that stores energy in an electric field, commonly used in filtering applications.

9
votes
To get the charge from the PVC into a capacitor, you could ground one side of the cap, and attach a wire to the other side of the cap. The end of the wire should preferably end in a fine point or … collection of fine points, and you sweep this over the charged surface of the PVC to collect what charge you can. If you use a smaller capacitor you will tend to get more voltage, but even a small …
answered Oct 31 '10 by JustJeff
8
votes
It's 'equivalent series resistance', and is somewhat frequency dependent. Basically it's the unavoidable ordinary resistance that comes along with the capacitor. Lower ESR means that the capacitor
answered Jul 16 '10 by JustJeff
8
votes
An ideal capacitor would not dissipate any power. Real capacitors dissipate a small amount of power whenever current flows through them, due to ohmic losses. Also, when operated under continuous AC …
answered Oct 19 '10 by JustJeff
2
votes
I'll go for the shortest-answer qualitative-take-away approach: A capacitor across DC rails is there, in effect, to short any AC signals that might otherwise get onto the supply rails, so the amount …
answered Aug 16 '11 by JustJeff
26
votes
No, having a higher rated cap will not somehow store up more voltage than is available in the circuit. You actually want a cap with a slightly higher voltage rating than the highest voltage you expect …
answered Apr 15 '11 by JustJeff
2
votes
dielectric does have a lower voltage, due to the properties of the dielectric, but this is not the same as having lower energy density. This is because higher energy density means more joules in the capacitor per volt on it, so it takes less voltage to store the same energy. …
answered Apr 2 '12 by JustJeff
8
votes
is, I believe, how one arrives at the situation of having a 'non-polarized electrolytic' capacitor. follow up - turns out that what might LOOK like two ordinary electrolytics are not, in fact, two …
answered Jun 17 '10 by JustJeff
14
votes
The basic electrical property of a capacitor is that the voltage across a capacitor cannot change instantaneously, whereas the basic property of inductance is that the current through an inductor … while capacitors conduct best at higher frequencies, inductors conduct best at lower frequencies. Another result is that if you put an AC current through a capacitor, the voltage will lag behind the …
answered Apr 7 '11 by JustJeff
30
votes
charge on a cap is a linear product of capacitance and voltage, Q=CV. If you plan to drop from 5V to 3V, the charge you remove is 5V*1F - 3V*1F = 2V*1F = 2 Coulombs of charge. One Amp is one Coulomb p …
answered Oct 7 '10 by JustJeff
3
votes
Everything has some resonance, so certainly you might be able to wrangle a capacitor value that, with the inductance in the rest of the circuit (chiefly to be found in your speaker), you could hit a … given frequency. But the problem here is, you have nothing to excite that resonance into action. If you fully charged the capacitor and slapped it onto the speaker, you'd get nothing more than a …
answered May 12 '13 by JustJeff
5
votes
(discounting Vce-sat of the PNP). This means that the capacitor now sees a voltage higher on the right side, so current begins to flow the other direction. While charging up, the cap built up a charge with … (+) on the left and (-) on the right, so the capacitor now looks like a tiny battery in series with the 0.88V on the 10 ohm, so it basically discharges into the base of the NPN, helping keep that …
answered Oct 30 '10 by JustJeff
39
votes
Blinking an LED can't done with just passive elements. Interestingly, you can accomplish periodically blinking a light, with a resistor and a capacitor, if your light happens to be a neon discharge … bulb, no current is passed until the voltage exceeds some threshold, which is the breakdown voltage of the neon gas. This allows the capacitor to charge up while the bulb remains dark. When the breakdown …
answered Jul 27 '10 by JustJeff
4
votes
Feedback can be used in any kind of amplifier circuit, not just in op-amp circuits. Feedback can be achieved by any component or network that will deliver a portion of the output signal back to the in …
answered Apr 29 '11 by JustJeff
10
votes
Problem is that energy in an inductor is due to current, and most all practical conductors have some resistance; this means that energy is continuously drained into heating the coil itself though I^2R …
answered Sep 25 '12 by JustJeff
1
vote
If they are physically small and have only two digits, I believe this is just the value in picofarads.
answered Aug 11 '11 by JustJeff

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