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An LED is a light-emitting diode. Lighting an LED is considered the "Hello world" of a circuit design, and it can be as simple as putting a series resistor or can get more complicated, involving PWM and multiplexing.

1
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Or a decade counter: (you are free to arrange the ten LEDs in a circle if you wish.)
answered Oct 27 '12 by rdivilbiss
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I've always been a fan of zinc and copper as a conductor which allows the circuit to close and conduct, (when introduced into saltwater.) Under normal circumstances it should not react to rain or tap …
answered Oct 17 '12 by rdivilbiss
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steady current for the LED. I would trust the datasheet and not the Digikey search page for the correct values. Of course you can always reduce the forward voltage and steady current until you get the …
answered Sep 1 '12 by rdivilbiss
2
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1answer
ideas on how I can count the number of clock pulses per second and display the results, (7 segment LED would be preferred)? …
asked Jul 2 '12 by rdivilbiss
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A USB port can only supply 5V at 500mA, which will not likely power more than two 1 watt LEDs (plus a resistor for current control.) It is hard to say without the datasheet for your LED. This … point you will need current limiting (resistor) to prevent your LEDs from attempting to pull too much current which leads to magic smoke. Frankly, I would suggest a constant current LED driver, many can be found on eBay. …
answered Sep 19 '12 by rdivilbiss
2
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Most micro-controller boards will give you a 0 (LOW) or 5V (HIGH). 5V will turn on the gate of an N channel MOSFET. Even low cost MOSFETS should allow 50-60 Volts from the drain to the source. IRF5 …
answered Apr 4 '12 by rdivilbiss
1
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LED strip. I would investigate this: TLC5940 which is a PWM controller for LEDs. It is ~ $4.20 vs. $70.00 USD and while it may require some external componenets it will be a superior and less expensive option. …
answered Sep 26 '12 by rdivilbiss
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How to provide a thermally-conductive, electrically-insulated mount for this PCB?"" How about electronics grade silicone, Just a thin coat.
answered Oct 27 '12 by rdivilbiss