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1

Any mux that can handle 12MHz signals (VHC153 or similar) should be fine. But I'd put the mux before the CS2300-03 PLL to help clean up any jitter introduced by the mux. Configure CS2300 to multiply by 1 or 256 depending on selected input.


1

With +/- 2.5V or single +5V supply, the OPA2134 input will barely be able to work with your DAC output. And if you used the datasheet example circuit, it is set to output a 2.1Vrms line level output, which is about 5.9Vpp, so if it were an ideal component, it would require at least 5.9V of supply voltage at minimum. It might be able to drive a line input ...


1

Place a 47 nF capacitor across the IC's power supply as the spec sheet says, fig. 22.


0

I installed the EC11B15242AF encoders, and they work perfectly. I used a regular soldering iron for electronics. I tightened the encoders to a flat and straight piece of metal, to keep the encoders lined up when soldering. I needed to add spacers to the ends of the shafts (to make the shafts longer by about 1mm), so that the push switch function would work ...


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The Bluetooth latency is due to the design of the communications protocols. Since, Bluetooth is a multi point connection system, it needs to buffer data (audio signal). The physical radio delay is less than 5 ms. Thus, without the buffering, latency can be well below 5 ms.


2

There's one thing you missed out: The gain-bandwidth product of the operational amplifier. Even if you are correct that the input filter has a cutoff frequency of 15.9 MHz in theory (neglecting the output impedance of the audio source), the actual cutoff is dominated by the operational amplifier because of the fact that the GBW of TL062 is 1 MHz. So it's ...


2

The impedance of an audio source would not be 0 ohms so the filter frequency would not be 16 MHz. That's why also 68nF you suggest is a bad idea, if source impedance is 1 kohm, the cutoff frequency would be 2 kHz. Typically audio inputs of professional devices have an RF blocking capacitor to filter out high frequency signals from getting to the amplifier ...


1

The formula is as described in the datasheet. The master clock is divided by 16, and divided by the tone period register value to get the tone frequency. Thus, to calculate the tone period value from the frequency you want, 440 Hz is calculated as follows : (2 MHz / 16) / 440 Hz = 284 in decimal, or 0x011C in hex. The tone period register is 12-bit so it is ...


3

Quick Overview I diagrammed things out about like the following (which includes some sympy script needed to perform a full solution): The automated solution is horribly long and not at all useful. So this implies a different approach is needed. I don't have the time to go through all of how I'd approach this. Not right now. But I may be able to outline what ...


0

I got the deoxit spray yesterday, and I sprayed all the encoders. I sprayed the encoder housing so the deoxit would work itself inside, and also sprayed the place where the shaft goes into the encoder housing, and operated the encoders. I did fast turns, and also turned them click by click to attempt to clean them. I repeated this 3-5 times. It seems to have ...


1

\$F_S\$ is the sampling frequency. You want to remove it. \$R_{ext}\$ represents the impedance of the load you expect. \$R_{ext}\$ and the 560 ohm resistor are effectively in parallel to each other. If \$R_{ext}\$ is much larger than 560 ohms, then it matters very little. If the output of the filter goes to an op-amp input, \$R_{ext}\$ will be very large ...


1

No, the Fs is the cutoff frequency you want for the filter. Rext is the load resistance of the device where the audio is being output. C is the capacitor for the lowpass filter. See the evaluation board schematics for example values for the passive filter.


3

Log time ago I try to analyze this circuit. For low frequency (bass) we have a "simple" case. simulate this circuit – Schematic created using CircuitLab And raw (high entropy) transfer function will look like this: $$H(s) = -\frac{R_2 + P_{3b} + C_2 R_2 (P_{3a} + P_{3b})s }{R_1 + P_{3a} + C_2 R_1 (P_{3a} + P_{3b}) s}$$ And for the max bass ...


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