# Tag Info

Accepted

### Boost Converter Efficiency Input Current

Points 1 and 2 are correct. Point 3: No circuit can create energy out of nothing, and there are always losses, so Pout < Pin. Thus if you want 17V 300mA (5.1W) you will need more than 5.1W on the ...
• 80.3k
1 vote

### Boost Converter Efficiency Input Current

Here's how I see it... Maximum input power is 5 volts x 500 mA = 2.5 watts You want 17 volts x 300 mA which is 5.1 watts You're not going to get this if you want the 17 volts to be continuously ...
• 467k

### Boost Converter Efficiency Input Current

Efficiency is defined as Pout/Pin. So, in order to get 300mA at the output, will I need at least 1.10A of input current from the main power source? Yes (or at least 1.07+ A). If $I_{in}=500$ mA, ...
• 26.1k

### I have a boost circuit. When the gate is low a short circuit appears

The switching loop is way, way too slow. Don't use float, and don't do any serial output from within the loop. The loop should look like this: ...
1 vote

### Output voltage for synchronous buck converter and synchronous boost converter

Thank you for comment and PDF of @VerbalKint, also answer of @bobflux, according to tip of they, I found formula that can simple and clear to understand why author give V_\mathrm{out} = \frac{1}{2}...
• 175

### Output voltage for synchronous buck converter and synchronous boost converter

Intuitive explanation: Let: Vin = constant $D$ = Switch duty cycle We're interested in steady state output voltage, which means at the end of the switching cycle, all variables (currents, voltages,...
• 80.3k