New answers tagged boost
4
votes
Accepted
Boost Converter Efficiency Input Current
Points 1 and 2 are correct.
Point 3:
No circuit can create energy out of nothing, and there are always losses, so Pout < Pin. Thus if you want 17V 300mA (5.1W) you will need more than 5.1W on the ...
1
vote
Boost Converter Efficiency Input Current
Here's how I see it...
Maximum input power is 5 volts x 500 mA = 2.5 watts
You want 17 volts x 300 mA which is 5.1 watts
You're not going to get this if you want the 17 volts to be continuously ...
2
votes
Boost Converter Efficiency Input Current
Efficiency is defined as Pout/Pin. So, in order to get 300mA at the output, will I need at least 1.10A of input current from the main power source?
Yes (or at least 1.07+ A).
If \$I_{in}=500\$ mA, ...
0
votes
I have a boost circuit. When the gate is low a short circuit appears
The switching loop is way, way too slow. Don't use float, and don't do any serial output from within the loop.
The loop should look like this:
...
1
vote
Output voltage for synchronous buck converter and synchronous boost converter
Thank you for comment and PDF of @VerbalKint, also answer of @bobflux, according to tip of they, I found formula that can simple and clear to understand why author give $$V_\mathrm{out} = \frac{1}{2}...
2
votes
Output voltage for synchronous buck converter and synchronous boost converter
Intuitive explanation:
Let:
Vin = constant
\$D\$ = Switch duty cycle
We're interested in steady state output voltage, which means at the end of the switching cycle, all variables (currents, voltages,...
2
votes
Why am I getting a low output voltage (5.98V instead of 12V) from a LM2623 stepup converter?
The datasheet has this warning (emphasis added):
8.2.2.2 Choosing The Correct C3 Capacitor
The C3 capacitor allows for the duty cycle of the internal oscillator to be > programmable. Choosing
the ...
0
votes
Why am I getting a low output voltage (5.98V instead of 12V) from a LM2623 stepup converter?
When laying out the PCB for a DC DC converter, parasitics introduced by the PCB traces can be a problem because it changes the design. Therefore reducing parasitics from the traces and vias will help ...
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