7 votes
Accepted

Do you know about topologies that look like this?

This is a 3-level single-phase boost converter. I think it has been originally presented in a paper at APEC in 1995: You can simulate this structure with SIMPLIS for instance and the below circuit is ...
Verbal Kint's user avatar
  • 21.9k
6 votes

Do you know about topologies that look like this?

Do you know about topologies that look like this? Yes. Is this right? Yes, that is one variant of the family of converters known as "3-level boost converters". How do I search it? Well, ...
Fabio Barone's user avatar
  • 1,933
5 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

The final state of "equilibrium" of this circuit will be when there's no longer any current flowing. That state can only be achieved when the voltage across the resistor is zero. If it's non-...
Simon Fitch's user avatar
4 votes

How to solve Thevenin and Norton circuit?

From what I remember, you need to short the circuit for voltage sources then open circuit for current sources. With that, I used it to solve for RTH which is 58 ohms (but i don't know if I got it ...
Andy aka's user avatar
  • 453k
3 votes

Why do linear components make linear circuits?

You can find the proof in elementary circuit theory texts such as Classical Circuit Theory By Omar Wing Theorem 2.1 A circuit composed entirely of linear elements is a linear circuit. Proof Let {v(t),...
Spehro Pefhany's user avatar
3 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

This doesn't make sense to me, since this would imply the capacitors have different charges. They do have different charges. Because they have different capacitances. Q = CV. V ends up the same for ...
Davide Andrea's user avatar
3 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

The solutions manual tells me that equilibrium means the voltages balancing. This doesn't make sense to me "Equilibrium" means "steady state": all circuit parameters are constant, ...
bobflux's user avatar
  • 75.8k
3 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

It looks like you have trouble with intuition, thinking the charges are going to be equal. Instead of doing the problem with commensurate capacitor sizes, which complicates things, use a much smaller ...
Neil_UK's user avatar
  • 165k
2 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

I was under the impression that in parallel, voltages are equal, ... No, the two capacitors are in series ... through R1. I am having trouble understanding the essential idea behind the solution. ...
Antonio51's user avatar
  • 12.7k
2 votes

Why is capacitor equilibrium based on balanced voltages and not balanced charges?

Charges are equal in series because the same current (which is charge/time) passes through each device. Note that if you start from a start where both capacitors are not at 0 V, then it's only the ...
jp314's user avatar
  • 18.8k
2 votes

How to solve Thevenin and Norton circuit?

In your example, you know you got \$-35\:\text{V}\$ and, when a \$10\:\text{V}\$ source was connected you then got \$1.125\:\text{A}\$. So the Thevenin resistance is \$\frac{10\:\text{V}-\left(-35\:\...
periblepsis's user avatar
  • 7,735
1 vote

Determining the region of operation of these two diodes

I'd recommend this: Check all possible combinations. It's not many. I'll start, you fill in the blanks. D3 in reverse bias, D4 in reverse bias Both diodes are blocking. This is impossible, because ...
Marcus Müller's user avatar
1 vote

Transimpedance amplifier with parallel RC

In steady state (DC) the capacitor is an open circuit so \$i_C = 0\$. Put another way, in steady state the voltage across the capacitor does not change so $$\frac{dv_c}{dt} = 0$$. That means that your ...
Null's user avatar
  • 7,598
1 vote
Accepted

How to emulate effect of mutual inductance?

Your attempt needs a fix. Try this: Verify it by inserting something to both sides and writing the KVL equations. M = the mutual inductance. It's the squareroot of the product of L1 and L2 only if ...
arnold8a's user avatar
  • 111
1 vote

How to emulate effect of mutual inductance?

the software package I want to use (JosephsonCircuits) to simulate does not allow any method to set the mutual inductance Are you sure? Mutual inductance is a feature listed in the first sentence of ...
Kuba hasn't forgotten Monica's user avatar
1 vote
Accepted

How to go with this RC circuit?

KCL Assigning \$v_1\$ to the node between \$R_1\$ and \$C_1\$ and assigning \$v_2\$ to the remaining node (with \$R_2\$ and \$C_2\$) the KCL says: $$\begin{align*} \frac1{R_1}v_1+C_1\frac{\text{d}}{\...
periblepsis's user avatar
  • 7,735
1 vote

Understanding how to read current direction when it is opposite to voltage direction

You can think of the polarity signs on the resistor as the problem telling you how to attach a multimeter across the resistor to measure it, with the red lead on the + symbol and the black lead on the ...
vir's user avatar
  • 17.5k
1 vote
Accepted

Analysis of NAND-based low-power monostable circuit

Most monostable circuits are based on a property of capacitors - the voltage across a capacitor cannot change instantaneously. Thus, if you yank one end of a cap from one voltage to another rapidly, ...
AnalogKid's user avatar
  • 19.6k

Only top scored, non community-wiki answers of a minimum length are eligible