5 votes

Is this equation in the photodiode model wrong?

If the paper's formula were true the Vout should have started from 4V. But it starts from 50mV. (?) Am ignoring the fact that OP's diode polarity is incorrect, and am assuming photocurrents produce +...
glen_geek's user avatar
  • 25.9k
5 votes

How to solve for \$i\$ using superposition?

First off, redraw the schematic. In fact, you should get into the practice of redrawing every schematic. Even those that already look good. Just do it. And do it every time. The practice is worth its ...
periblepsis's user avatar
  • 8,990
5 votes

I made a 3-phase power rectifier circuit with "ideal" diodes. Is there anything I should change?

The "ideal diode" circuit is intended for switching between two DC sources with minimal losses. It has a limited voltage compliance range, in the sense that both ends of the "diode"...
Dave Tweed's user avatar
  • 173k
5 votes

Resolving this circuit diagram

V2 is an ideal voltage source. By definition, V2 is is fixed at "V2" independent of all other circuit elements. V3 = V2 because V2 IS the same node as V3. By definition, all nodes have the ...
MOSFET's user avatar
  • 3,110
3 votes
Accepted

How to solve for \$i\$ using superposition?

The simplest but most laborious method is the Superposition principle,Below I examine the various cases (see photo):
Franc's user avatar
  • 1,261
2 votes
Accepted

Error analysis in analog-to-digital converter (ADC) applications

May I know from where that loss equation(log2(4.13) = 2.05) came Lets try this approach. If I asked what \$log_2(256)\$ is, the answer you would get is 8. 256 is equivalent to the number of LSbs ...
Andy aka's user avatar
  • 457k
2 votes

I made a 3-phase power rectifier circuit with "ideal" diodes. Is there anything I should change?

I'm not sure if you are aware but your circuit doesn't make use of the MOSFETs properly i.e. you are not using the MOSFETs as ideal diodes. Instead, you are using their body diodes which is no ...
Rohat Kılıç's user avatar
1 vote

Resolving this circuit diagram

why wouldn't V1 have any impact on the voltage at V3 in this diagram? Imagine that V2 was chosen so that it produced 0 volts. I mean, it can have any value you want i.e. all are valid but, imagine it ...
Andy aka's user avatar
  • 457k
1 vote

Resolving this circuit diagram

Because node 3 (V3) is defined by voltage source V2. If there would be a resistor in series with V2 connecting to the right terminal of R1, then there would be a contribution of V1 as well.
Designalog's user avatar
  • 4,040
1 vote

How does positive current flow out of the negative terminal (2A) and into the positive terminal (2A)?

Not like a resistor, just like an ideal voltage source that maintains the same voltage difference across its terminals regardless of how much current flows into or out of it and in what direction.
vir's user avatar
  • 18.5k
1 vote

Problem with a diode-circuit design

Solution could be something like this ... Ideal conditions. where R1 = ~ 800 Ohm and R2 = ~ 431 Ohm ... Simulation could say something like this ... Diode generic.
Antonio51's user avatar
  • 13.3k
1 vote

Problem with a diode-circuit design

Kind of hoped you'd write up what you worked out in comments. (Very good!) But as I already have the image prepared, I will write up your thoughts below. Yes, as you worked out you need three diodes (...
periblepsis's user avatar
  • 8,990
1 vote
Accepted

How to solve for V using source transformation method

I'm confused on how to solve for 7 A current source using source transformation method, what would the circuit even look like? It's the reverse process of what you did earlier. This time you ...
Andy aka's user avatar
  • 457k
1 vote

How to solve for V using source transformation method

The wanted voltage is between nodes A and Ground. The writer of the problem has intentionally drawn the wanted voltage like it somehow was a private property of a single resistor to confuse those who ...
User 0058933's user avatar
1 vote
Accepted

Amplitude modulation problems

A classic amplitude modulator is the diode bridge one as in the figure:
Franc's user avatar
  • 1,261
1 vote

Amplitude modulation problems

That's not a crystal oscillator. I can't think of a reason why that circuit SHOULD work. Where on earth did you find it?
Fred's user avatar
  • 356
1 vote

The effect of input and output impedance

It is assumed that at least one of the two quadrupoles presented by the applicant is active. The configuration is the well-known Series-Shunt and the study must be done using the H parameters and the ...
Franc's user avatar
  • 1,261

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