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10

If you are interested in my ideas: Here you go in order. Read the datasheet for the charger carefully. Search for terms like 'short circuit protection' or 'current limit'. Most devices will have some sort of hiccup implementation. My guess is that sufficient safety measures are already included and qualified - so no need to complicate your design. Please ...


8

Many people use P-MOS in the linear region to avoid the inrush current during the initial capacitor charging. It is a working approach of course, but it is hard to hold a MOSFET in the linear zone for a long time (all charging process). I prefer charging through a shunt (like 47 ohm) and once the capacitor reaches a certain voltage (like 3 V) when the inrush ...


3

If there are three different solar arrays with different size, each array has a different optimal voltage and current for maximum power output. So each array needs its own inverter to find the individual maximum power point. If the arrays are connected in parallel with blocking diodes, it is possible that only the array with the highest voltage will be used ...


1

You can use numerical methods to solve this. The derivative can be approximated by a delta. Here it is in Excel. You will need to substitute your I(V) data. You can use a lookup function for that. For my example, the time interval is coarse, you will want to use a finer increment. With "show formulas" enabled:


1

Your PX603 or PX613 pressure sensor can operate with an excitation voltage of 10 to 36 volts. Your 25V power supply is fine. The sensor will only take the current it needs from the power supply. That's the 3 milliamperes mentioned in the datasheet. It doesn't matter if your power supply can deliver just 3 mA, or if it can deliver 50A. The sensor will ...


1

Wire, connected to central tap, conduct current from 0A, in case the load is symmetrical, to 4A maximum. Keep the same wire size.


1

Your method 2 is correct. You might find it useful to learn about load lines. These are useful when the device (the LED) doesn't behave in a linear fashion like a resistor. Figure 1. Various loadlines for a 5 V supply and various LED types. Image source: Loadline resistance graphic tool. Each loadline is drawn from 5 V, 0 mA to 0 V and the current ...


1

When calculating the current through an LED and a resistor in series, you need to take into account the voltage drop across the LED. So method 2 is the correct one.


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