Hot answers tagged

10

Look for the Vgs at which Rds(on) is guaranteed. Vgs(th) is the voltage at which it is mostly off. Edit: From your linked datasheet: If you have 5V drive you can count on 12m\$\Omega\$ maximum Rds(on) with the MOSFET at room temperature (maybe 50% higher with it hot). If you have 10V drive, it is lower by almost half. There is no guarantee for 3.3V so I ...


5

If you want to know how the drain source characteristic changes for different gate voltages try this graph on page 6: - With \$V_{GS}\$ at (say) 3.5 volts, the drain can conduct (for example) about 35 amps with a volt drop (\$V_{DS}\$) of around 2.5 volts i.e. a power dissipation of 87.5 watts (not fantastic). \$R_{DS(ON)}\$ will be 2.5/35 = 0.07 ohms. ...


4

I believe this whole question is based on the misinterpretation of the oscilloscope screenshot shown first, before adding a capacitor & resistor to the LM393 output. You said: I want to change my square wave signal [...] 5 volts to 0 volts This is what is shown in the first image anyway! In the first picture, it is my original square wave coming from ...


2

When you set your power supply to 16 volts and 5 Amps, the supply will maintain 16 volts while delivering UP TO 5 Amps. The actual current delivered will be determined by the resistance of the load. If the supply delivered 0.11 amp at 16 volts, by Ohm's Law (V = I x R), the load resistance was about 145 Ohms, and the power dissipated in the load was about 1....


2

You can never "force" a current higher than 0.11A through a 120 ohm resistance while maintaining the voltage at 16V. You can either set the voltage or the current, not both. Your power supply is (within limits) a voltage supply, so it sets the voltage. If you want to increase the current, you need to either increase the voltage, or decrease the ...


2

Look at the charger end and you can determine the polarity with a multimeter. In fact, the information is often printed on the power supply centre pin positive or negative... positive centre is most common but never guaranteed so always check. Your port looks like it is rectangular so check.


2

If we have a DC sine signal. Can we say that capacitors and inductors have impedance despite not being AC? When we talk about the impedance of an inductor or capacitor we are talking about one single frequency (a sine-wave) with no DC offset: - $$|X_L| = 2\pi F L$$ And $$|X_C| = \dfrac{1}{2\pi F C}$$ Where \$F\$ is a single operating frequency in hertz. $$\...


2

Capacitors and inductors always have impedance, at all frequencies, including 0 which is DC. There is no DC sine. At DC, frequency is 0, so capacitor has impedance of infinity so it is an open circuit and inductance has impedance of zero so it is a short circuit. AC signal has a frequency, and ideal square wave consists of harmonic frequencies up to infinity,...


2

The answer is in the chip manufacturer's FAQ section about the chip. The limit is how much the silicon heats up, so it depends on the ambient temperature. At 85 C ambient temperature, it can take 40A for infinitely long. Or 20A continuously at 150 C ambient. It can also take short 200A pulses but they have to be limited so that they are short and do not ...


2

The answer is yes. The circuit inside the handle would be a buck converter. Going by the available information on the Stalker Radar Gun and its accessories, 2 battery configurations appear feasible: Six 1.2V 2500mAh rechargeable NiMH batteries in series Two 3.6V 2500mAh rechargeable Li-ion batteries in series. They would be capable of 2 hours of continuous ...


1

A good place to start would be to determine what kind of circuit the handle uses. Is it is possible you can find the name of the IC, and then determine its function in the datasheet. The circuit overall looks a bit like a buck converter. If that's the case you should be able to replace it with a battery. All though I might be mistaken. Which is why I would ...


1

Probably. The 2/3 normal voltage might cause 100% duty cycle operation of the battery charger, meaning current SOARS far beyond tolerable operating currents. Your switching FET may have smoked. Or the energy_transfer inductor may have gone into saturation, overheating either the inductor or the FET.


1

A 12 V source will deliver whatever current to the modem it wants to draw. There is not only no requirement for a current limiting resistor, but any resistor large enough to limit current will be positively harmful for the modem's operation. A more serious problem is the tolerances on the voltage. Does the modem need 12 V +/- some tight tolerance which is ...


1

Pulsed DC voltage from a single phase bridge rectifier will mean that the current in the feild and hence the armature will be pulsing to some extent .The total inductance would have to be infinite to make the current waveform pure DC.The pulsing current will cause more motor losses than pure DC like a battery.But the losses are lower than a straight 230 VAC ...


1

There are two reasons that DC and a spectrum analyser generally don't mix. The first 'easy to understand' reason is that their 50 Ω input impedance will be a real 50 Ω resistor, or an attenuator with real resistors, and too much power will damage it. You don't need many volts DC input for 100 mW or so, only a little over 2 V. Many signals that you'll want to ...


1

If the control in implemented properly, you should be able to run the motor at half the speed that would be possible with 24 volts. For the same load torque, the current would be the same as with 24 volts.


Only top voted, non community-wiki answers of a minimum length are eligible