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(TY AG I read too fast, and thought load is on the battery rather than on the charger which is OK) Apologies Certainly, you can load the charger and reduce its capacity while charging the batteries at a lower CC rate. Previous Answer to a different understanding. If you had the load on the battery side, you should cut charging to the battery if it is ...


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Either your battery is 10 kWh or 10 kAh but not normally referred to as 10 kVAh (a term we might use in AC circuits due to power-factor). If your battery's internal resistance is 320 mΩ then the maximum current you could draw into a dead short (not recommended) would be \$ I = \frac V R = \frac {50}{0.33} = 150 \ \text A \$ but you would have zero volts at ...


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TL;DR short answer To protect PSU’s that failed catastrophically during Hipot tests in factory, I modified the HV supply probe to insert a string of 1/4W Resistors so if it failed the xx uA limit the capacitance would not dump amps into the device. You ought to consider doing the same at exit after parasitic capacitance, and use static dissipating material ...


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The beeper does not draw a constant 25 mA at all voltage levels between 3.5 V and 5.0 V, and we do not know what the actual current draw is (<=25 mA could mean 2 or 22). So the best we can do now is make some assumptions to at least get a feel for a solution. Worst case is that the buzzer draws the full 25 mA at all operating voltages, and shuts off at 3....


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