5

You can use inverting charge pump, buck-boost voltage inverter or a virtual ground op amp based solution to split rails. This is one example component which can provide \$-15\,\mathrm{V}\$. It is a simple dc-to-dc converter module. Part number: P7805-Q24-S15-S Do not miss to notice the pin numbering in both configuration.


4

Because the N-channel MOSFET can carry higher current and it is cheaper then its similar size counterpart P-channel MOSFET. N-ch MOSFET can be used also as high side switch, but it requires an additional charge pump. The shunt is placed on lower side, because the common mode voltage would be too high for the operational amplifier. Again, it is possible to ...


3

Notice that you have a current source and not a voltage source. In this case, when using Thevenin you should replace the current source by an open circuit to find the equivalent resistance (as opposed to replace by a short if you have a voltage source). Therefore, the equivalent resistance will not be R1//R3 + R2 as you've assumed. Actually the solution is ...


2

A coworker suggested that the "code is creating latches for the pipeline segments, instead of clocked flip flops". The two code segments are totally different. The first is combinatorial logic, the second is a register. The behavior of the two is also total different. In the first what you call a 'clk' is not giving you the behavior of a real clock at all, ...


1

Just answering the question (title) - without reference to the presented diagram: Yes, of course, a resistance can be negative !! The I-V characteristic of a tunnel diode (Esaki diode) shows in a certain range a negative dynamic (differential) resistance (hence, not a static negative resistance) There are special active circuits (NIC- Negative Impedance ...


1

The reason the coil energy is negative is because the coil is sourcing power. If you do the same for the resistors, their energy is positive, because they're dissipating it. The energy for the capacitor is negative as well, because the sign of the current reverses for the capacitor as it is decharging.


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