2
votes
Why can't I directly measure the voltage drop on the feedback capacitor in a charge-sensitive amplifier?
Short answer:
It's because you want to measure a charge, not a voltage.
Longer answer:
There is a saying in german: "Wer misst, misst Mist" ("Who measures, measures crap"). ...
- 1,579
2
votes
Multiple feedback single supply
I agree that the +inputs of the opamps and the input signal must be at half the supply voltage.
Your schematic was larger than my neighborhood and had tiny text because the parts were WAY too far ...
- 2,327
1
vote
Accepted
Unexpected low output from basic inverting OPA134 attenuation circuit
Not knowing anything about pickups, is the circuit you posted a standard design for piezo guitar pickups?
The model of a piezo pickup far below resonance is modeled as a capacitor in series with a low ...
- 3,993
1
vote
How to practically find the amplitude of a high frequency signal?
The signal will be anywhere from ~1-24V p-p and (hopefully) useful
within ~0.05Hz to 10MHz, though feel free to tell me if this is a
lofty goal.
The big issue is the bandwidth of the amplifiers and ...
- 63.7k
1
vote
Why can't I directly measure the voltage drop on the feedback capacitor in a charge-sensitive amplifier?
A typical use case may clarify this. If we have a force sensor containing a crystal with, say, 50 pF, this provides a charge once a force is applied. A voltmeter would discharge this sensor signal as ...
- 1,859
1
vote
Accepted
How do I interface a low power controller with a higher power load?
The obvious solution (to an engineer in this field) is an emitter follower:
simulate this circuit – Schematic created using CircuitLab
For reasons I explain below, that solution has some ...
- 7,785
1
vote
How do I interface a low power controller with a higher power load?
With a 150 Ohm resistance, that is pretty easy to buffer with a low impedance voltage driver that can drive 40 mA with low saturation limits on supply. some Op Amps can do this, but if you are ...
- 136k
1
vote
How are formulas for "in the loop compensation" of capacitive load derived?
There's no need to go through the analysis of the transfer function, again, since @Verbal Kint has already posted a link to a good answer, and @jonk does expand, too, in the comments. Instead, I'll ...
- 17.7k
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