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Is this a safe way to measure mains power on an oscilloscope?

Yes, this is a safe method. But you could also build a capacitive voltage divider in a safe way, using a couple of small capacitors instead of the transformer. That might make for more accurate ...
Roland's user avatar
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2 votes

Expanding oscilloscope bandwidth by amplifying higher frequencies

Because you can 'unlock' a higher bandwidth, the implication is that, internally, the frequency response is being controlled by DSP filters. The overall frequency response of DSP filters is extremely ...
Peter Smith's user avatar
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1 vote

Expanding oscilloscope bandwidth by amplifying higher frequencies

Like you said, it is possible to expand the bandwidth by unlocking the system. Legal way to do it is to pay the "relatively large fee". For some scopes, illegal ways have existed. No. Or ...
Justme's user avatar
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2 votes

Expanding oscilloscope bandwidth by amplifying higher frequencies

Generally speaking, bandwidth is the -3 dB point of the scope's analog front end. So if the scope's bandwidth is 100 MHz then a 100 MHz signal coming to the channel will be attenuated by -3 dB, or the ...
Rohat Kılıç's user avatar
3 votes

“Old school” Virtual Oscilloscope SWF

I'm currently on a mobile device, so I can't check the website myself, but: Emulating old software in the context of education is (sadly?) a common problem. For flash, ruffle.rs is the usual tool. You ...
sina bala's user avatar
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1 vote

Siglent SDS1104X-E Integrate Function - Units of Measure

Strange unit to choose, \$\text{Wb}\$, but \$\rm{Wb =V\cdot s}\$, so you're good. Perhaps they want to avoid confusion for people thinking \$\rm{Vs}\$ means volts. That white trace looks exactly like ...
Simon Fitch's user avatar
4 votes

Signal gets amplified in oscilloscope

Set the channel to 10x and set the scope probe to 10x. They should always match. It's almost always better to use 10x because the bandwidth will be better. The input-referred noise will be more ...
Spehro Pefhany's user avatar
0 votes

Emitter circuit on a breadboard

Your amplifier seems to be working. The problem is that your output signal is too large. The output needs to be within the range of the supply voltage. The gain is ~180, which gives an output of +/-...
Adam Haun's user avatar
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1 vote

Emitter circuit on a breadboard

You show 0.1V input in the simulation, yet ~5V on the breadboard. The waveform appears to be normal operation for such heavy overdrive. You will observe shifts in bias voltages for the same reason. ...
Tim Williams's user avatar
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1 vote

Is this modified or pure sine wave...or something else?

It looks like just L output filter where 5ms is positive supplying cycle, 5ms just discharging L through freewheeling diode, 5ms negative supplying and another 5ms discharge L via freewheeling diode. ...
Michal Podmanický's user avatar
0 votes

Is this modified or pure sine wave...or something else?

The shape certainly does not look like a pure sine, but then again no source will give an absolutely pure sine and this might be good enough. It also seems from your question that you measured current,...
Jos Bergervoet's user avatar
3 votes
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Unknown signal source

These results are not unexpected at all. Nothing to do with the TV. Try it with charging bricks or other switching "brick" power supplies. it is unlike any switching noise I have seen ...
Kuba hasn't forgotten Monica's user avatar
3 votes

Issue with LED and capacitor circuit

The voltage source and the capacitor are in parallel. Therefore, whatever voltage is across one, is also across the other. The the "pulse" directive is gives an "ideal" response. ...
Math Keeps Me Busy's user avatar
2 votes

Issue with LED and capacitor circuit

In Spice, voltage sources have zero impedance by default. Whatever voltage they are set to is what you will measure across them regardless of what other components they are connected to. So in your ...
GodJihyo's user avatar
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