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This circuit might not have a state space form (the way it is drawn and defined now). The output equation is (by current division formula) \$Y = \mathbf{0} X + D U\$ where \$U = I_c\$ and $$D = \frac{R_1+sL_1}{R_1+sL_1 + R_2 + sL_2}$$ Since the output is fully defined by the feed-through matrix \$D\$ and the input \$U\$, the state vector \$X\$ and the ...


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I hope I am not wrong but I think that the solution is very simple. Due to the fact that the transition between both the state space models has been done via application of the transform matrix \$\mathbf{T}\$ on the system matrix \$\mathbf{A_T}\$ and the input matrix \$\mathbf{B_T}\$ I think that I can simply substitute the following formulas into the ...


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