jjstcool
  • Member for 7 years, 5 months
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2 answers
3 votes
2k views
Watchdog timer issue - AVR ATmega324PA
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4 votes

Yeah, that is because after the watchdog fires, you have to reset the corresponding flag before main starts again (there is a register where you can read out, what caused the reset) and to disable the ...

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1 answers
2 votes
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Circuit design: detecting oscillating magnetic fields with pick-up coil, amplifier, filter
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2 votes

up to where you estimated the voltage I understand what you do and it is correct. Now, the As such, we can set Vout=(1 V/μT)B and solve for the ratio of R1/R2 that solves properly calibrates the ...

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1 answers
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Some questions on a passive network's transfer function and time domain response
2 votes

Yes you are basically correct with your observations. So I think what pole’s imaginary part indicates is the impulse response’s frequency. Is that correct? Yes. Laplace transform is a tool to ...

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1 answers
2 votes
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How to build LED dimmer for room illumination - PWM, low pass filter?
2 votes

This is a good idea. Theoretically you could use the pwm as is to dim the lights since an LED shines brighter the longer the on-periods are. Your concern about sending waves might be negligible as ...

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2 answers
2 votes
406 views
Fourier Transform help
1 votes

Your mistake is in the very last step: the derivative of \$e^{-|w|}\$ is different as you calculated. The (I believe) correct answer is as shown here Since I'm not totally sure, just expand your ...

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1 answers
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What is the conductance of this LC tank?
1 votes

looks like your guess is right. Imagine frequency = 0, then the inductor becomes a conductor and only \$R_L\$ is responsible for the impedance. on the other end of the spectrum, \$\omega \rightarrow \...

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2 answers
1 votes
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Input capacitance IGBT and MOSFET
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Miller capacitance is nothing that you can easily measure with a cap-meter. The effect comes from the voltage on one pin falling such that less voltage difference is seen on more of the area, such ...

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2 answers
2 votes
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RLC Series circuit V(t) = Vss(t) + Vt(t)
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You messed up with the math. I don't fully follow, what you are doing, it doesn't seem totally wrong, but you certainly miss some stuff. First of all: you get a non-damped solution with your ...

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Amplifier design: feedback with unclear poles
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I found the answer to my question by accident: Just for those who are still interested in what I asked. Now everything makes sense and gets way clearer. Thanks for the help anyways! Edit : I made up ...

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2 answers
1 votes
698 views
Output voltage of bridge rectifier
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Your intuition is right for the first cycle. Imagine at first there is \$V_z\$ positive, say 2V and E is 1V, so there is a voltage drop in forward direction of 1V and the current \$i_0\$ starts to ...

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