Timeline for Why don't all motors burn up instantly?
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Mar 16, 2014 at 15:37 | comment | added | peterG | @BrianDrummond Thanks yes that's exactly what I meant / would have replied! | |
Mar 16, 2014 at 11:28 | comment | added | Andreas Wallner | You say that the current the op calculated will only be drawn for an instant. As you correctly said, the current is drawn when the motor is fixed (e.g. when measuring the short circuit voltage with nominal voltage). When switching on the motor this will not happen because of the inductance of the motor windings. In conjunction with the winding resistance, the current will rise exponentially. | |
Mar 16, 2014 at 9:57 | comment | added | Friend of Kim | @BrianDrummond Aha, so there might be some protective circuitry in the ESC. Thank you for your answers. | |
Mar 16, 2014 at 9:41 | comment | added | user16324 | By motors "of any size" PeterG might mean those in railway locos (not models!) With an RC car, what happens would depend on how good the speed controller is. If it's cheap, the motor could well burn out. | |
Mar 16, 2014 at 9:31 | comment | added | Friend of Kim | @peterG So if I make a RC car, it will not burn up if it gets stuck and the motors can't turn? (Because of the starting circuitry.) | |
Mar 16, 2014 at 9:28 | vote | accept | Friend of Kim | ||
Mar 16, 2014 at 3:32 | comment | added | Kaz | Acceleration is not really acting as a "resistance". It's acting as an energy sink. Energy goes into motion, and that energy is not available for being dissipated as heat. The energy consumption does appear as Ohmage under a simple application of the power law. | |
Mar 16, 2014 at 2:38 | comment | added | peterG | For this reason motors of any size have starting circuitry that limits the current until rotation is under way. | |
Mar 16, 2014 at 2:17 | comment | added | Eric | No, the rotation of the armature causes a voltage to be generated in the windings that opposes your voltage source such that the effective voltage across your motor is lowered and therefore less current flows. | |
Mar 16, 2014 at 1:38 | comment | added | Friend of Kim | So what you really say, is that the acceleration of the rotation is basically acting as a resistance? | |
Mar 16, 2014 at 1:30 | history | answered | Dave Tweed | CC BY-SA 3.0 |