Timeline for Why does a capacitor act like a short-circuit during a current impulse?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 27, 2014 at 19:30 | vote | accept | user29568 | ||
| Apr 10, 2014 at 14:57 | comment | added | Andy aka | A current impulse (infinite di/dt) can only pass through a perfect inductor if the terminal voltage across the inductor is infinite. In a practical world, an inductor has self-capacitance and this means the impulse current bypasses the "magnetic" side of things and appears to pass through the inductor, but it doesn't theoretically. You haven't really stated what you would like to achieve (as I asked) - I've given you the best answers I can give but without a better idea of what you need (not how you want to implement it) I can't really help. | |
| Apr 10, 2014 at 14:35 | comment | added | user29568 | @Andyaka Speaking hypothetically(because impulses aren't physically realizable), the only way for a current impulse to pass through an inductor is using a current impulse source or voltage impulse source? | |
| Apr 10, 2014 at 14:32 | comment | added | Andy aka | @user29568 there is no such thing as a current impulse through an inductor - it would take infinite voltage to create one. Remember, because V = L\$\dfrac{di}{dt}\$, if di/dt were infinite then so would V. | |
| Apr 10, 2014 at 14:29 | comment | added | Andy aka | @HL-SDK why don't you do that dude, there's plenty of room to make your own answer. | |
| Apr 10, 2014 at 14:29 | comment | added | user29568 | @Andyaka I am asking out of curiosity: I wanted to know if there exists a certain circuit design that uses a step voltage source to create a current impulse through an inductor using capacitors. In light of HL-SDK comment, I would appreciate a physical interpretation as well--as near as that might be. | |
| Apr 10, 2014 at 14:23 | comment | added | HL-SDK | Judging by the question, the asker might be served well with a physical interpretation of what is going on (displacement current/dipoles and that magnetic thing that makes inductors work) | |
| Apr 10, 2014 at 14:22 | comment | added | Andy aka | The impulse of current when the inductor is in series with the capacitor will be reduced dramatically. Maybe if you state what you are trying to achieve I can help better? | |
| Apr 10, 2014 at 13:50 | comment | added | user29568 | Thank you :) One more question if there is a step source in a circuit can there be an impulse of voltage or current in it. Or are impulses only spawned from impulses. The caveat I'm thinking of is a votlage step across a capacitor that would give rise to a current impulse, but is their a way to transfer that sudden current impulse to a inductor. Is it by putting it in series with the capacitor? | |
| Apr 10, 2014 at 13:45 | comment | added | Andy aka | Start with the basic inductor formula of V = L\$\frac{di}{dt}\$ and integrate both sides to find i | |
| Apr 10, 2014 at 13:37 | history | answered | Andy aka | CC BY-SA 3.0 |