Timeline for How much power do I need to transmit a radio signal through a solid ice crust 100 km thick?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 14, 2014 at 8:21 | comment | added | Spehro 'speff' Pefhany | dB is 10*log(x/y) where log is base 10 and x/y is a ratio of powers. If x = 1 gigawatt and y = 0.003W, that's about 115dB. | |
| Apr 14, 2014 at 7:09 | comment | added | jumpjack | How do you "pass" from attenuation dB to needed power? (e.g. from 115 dB to 1 MW) | |
| Apr 13, 2014 at 18:26 | comment | added | Andy aka | No, nothing deeper. Interesting article and I'm still trying to work out what the results mean - it seems they're trying to infer distance by looking at reflections. Maybe you have a better take on this. It does seem to contradict the NASA results in my answer and I'm genuinely scratching my head to the large disparity. | |
| Apr 13, 2014 at 18:03 | comment | added | Spehro 'speff' Pefhany | Edited.. or is it a deeper question? | |
| Apr 13, 2014 at 17:58 | history | edited | Spehro 'speff' Pefhany | CC BY-SA 3.0 |
Added attenuation length
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| Apr 13, 2014 at 17:52 | history | edited | Spehro 'speff' Pefhany | CC BY-SA 3.0 |
Added attenuation length
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| Apr 13, 2014 at 17:45 | comment | added | Andy aka | I'm unsure what "attenuation length" actually means. | |
| Apr 13, 2014 at 15:35 | history | answered | Spehro 'speff' Pefhany | CC BY-SA 3.0 |