Timeline for When would I use a voltage regulator vs a voltage divider?
Current License: CC BY-SA 3.0
14 events
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| Jul 30, 2018 at 21:03 | comment | added | bitsmack | Thanks @PeterGreen, that's true. If I remember correctly, that LDO had ~200mV dropout. I had the system enter a low-power mode at Vbat = ~3.5V... | |
| Jul 30, 2018 at 15:02 | comment | added | Peter Green | Be aware that "3.7V" is only a nominal voltage, if you use a LDO to go from a 3.7V cell to 3.3V your regulator is likely to start to drop out long before the battery is fully discharged. | |
| S Mar 24, 2016 at 5:46 | history | edited | uint128_t | CC BY-SA 3.0 |
More grammar fixed
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| S Mar 24, 2016 at 5:46 | history | suggested | awiebe | CC BY-SA 3.0 |
grammar fixed
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| Mar 24, 2016 at 5:43 | review | Suggested edits | |||
| S Mar 24, 2016 at 5:46 | |||||
| Apr 17, 2014 at 12:25 | vote | accept | Pete | ||
| Apr 16, 2014 at 18:31 | comment | added | bitsmack | @kmort Glad to help :) | |
| Apr 16, 2014 at 18:29 | comment | added | kmort | @bitsmack Yes, makes great sense. I should have thought about that a bit more. Thanks for your help. :-) | |
| Apr 16, 2014 at 17:48 | comment | added | bitsmack | @kmort Imagine you are dividing 10V down to 5V. You use two 500-Ohm resistors to do the division. So, now, you have 10(V)/1000(Ohm) = 10mA flowing through the divider. Now, add your load. This load goes in parallel with the bottom resistor, which skews the resistor divider calculations, and changes the voltage ratio. If your load is fixed, then you can calc the adjusted divider values. A good rule of thumb is to draw less than 10% from the divider's center node, so you don't perturb the ratio very much. But now, you are using 10x your required current just through the divider! | |
| Apr 16, 2014 at 17:24 | comment | added | kmort | "the divider can't source any significant current" Why is this the case? | |
| Apr 16, 2014 at 16:41 | history | edited | bitsmack | CC BY-SA 3.0 |
Clarity...
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| Apr 16, 2014 at 13:36 | history | edited | bitsmack | CC BY-SA 3.0 |
added 762 characters in body
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| Apr 16, 2014 at 10:47 | comment | added | Joe Hass | I think it's worth mentioning that your discussion of efficiency with multiple supply rails applies only to switching regulators and not to linear regulators. | |
| Apr 16, 2014 at 4:30 | history | answered | bitsmack | CC BY-SA 3.0 |