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explain difference between continuous and discontinuous conduction mode
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Jon Watte
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There are two parameters that matter in the boost converter: Duty cycle, and switching frequency. (And a third: whether it's in continuous or discontinuous conduction mode)

You are saying that the capacitor "drains" when you supply the load -- this means that you're not switching the converter fast enough to re-"fill" the capacitor.

The reason for this may be that there's too high resistance in your inductor, or your transistor can't sink enough current (typically, power N-channel MOSFETs are used,) or your battery source has too high internal resistance.

A 2N2222 is not a power transistor. Also, you don't indicate how much current your oscillator will source. Given that you're using a BJT, the amount of current through the transistor is directly proportional to the amount of current out of the oscillator (up to the saturation point of the BJT.) Without knowing more, I would suspect using a higher-performance transistor with a higer switching rate (say, 20 kHz) and a lower-resistance inductor would improve the performance you see.

Also, the schematic shows a sine generator. You want to use a square wave for a boost converter.

Hook up a scope to various points in your circuit, to measure how it's doing, and this will tell you where it goes wrong.

There are two parameters that matter in the boost converter: Duty cycle, and switching frequency.

You are saying that the capacitor "drains" when you supply the load -- this means that you're not switching the converter fast enough to re-"fill" the capacitor.

The reason for this may be that there's too high resistance in your inductor, or your transistor can't sink enough current (typically, power N-channel MOSFETs are used,) or your battery source has too high internal resistance.

A 2N2222 is not a power transistor. Also, you don't indicate how much current your oscillator will source. Given that you're using a BJT, the amount of current through the transistor is directly proportional to the amount of current out of the oscillator (up to the saturation point of the BJT.) Without knowing more, I would suspect using a higher-performance transistor with a higer switching rate (say, 20 kHz) and a lower-resistance inductor would improve the performance you see.

Hook up a scope to various points in your circuit, to measure how it's doing, and this will tell you where it goes wrong.

There are two parameters that matter in the boost converter: Duty cycle, and switching frequency. (And a third: whether it's in continuous or discontinuous conduction mode)

You are saying that the capacitor "drains" when you supply the load -- this means that you're not switching the converter fast enough to re-"fill" the capacitor.

The reason for this may be that there's too high resistance in your inductor, or your transistor can't sink enough current (typically, power N-channel MOSFETs are used,) or your battery source has too high internal resistance.

A 2N2222 is not a power transistor. Also, you don't indicate how much current your oscillator will source. Given that you're using a BJT, the amount of current through the transistor is directly proportional to the amount of current out of the oscillator (up to the saturation point of the BJT.) Without knowing more, I would suspect using a higher-performance transistor with a higer switching rate (say, 20 kHz) and a lower-resistance inductor would improve the performance you see.

Also, the schematic shows a sine generator. You want to use a square wave for a boost converter.

Hook up a scope to various points in your circuit, to measure how it's doing, and this will tell you where it goes wrong.

Source Link
Jon Watte
  • 5.8k
  • 27
  • 37

There are two parameters that matter in the boost converter: Duty cycle, and switching frequency.

You are saying that the capacitor "drains" when you supply the load -- this means that you're not switching the converter fast enough to re-"fill" the capacitor.

The reason for this may be that there's too high resistance in your inductor, or your transistor can't sink enough current (typically, power N-channel MOSFETs are used,) or your battery source has too high internal resistance.

A 2N2222 is not a power transistor. Also, you don't indicate how much current your oscillator will source. Given that you're using a BJT, the amount of current through the transistor is directly proportional to the amount of current out of the oscillator (up to the saturation point of the BJT.) Without knowing more, I would suspect using a higher-performance transistor with a higer switching rate (say, 20 kHz) and a lower-resistance inductor would improve the performance you see.

Hook up a scope to various points in your circuit, to measure how it's doing, and this will tell you where it goes wrong.