Timeline for How can I regulate a 5V battery?
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Apr 21, 2014 at 23:36 | vote | accept | Val Blant | ||
Apr 21, 2014 at 23:35 | comment | added | Val Blant | Hmm, this is strange. The datasheet for ADP1613 says that it can handle 2A of current, yet their design tool I downloaded refuses to do the calculation for me, b/c it thinks that ADP1613 can't handle more than 0.3A. Hope its a bug in the design tool. I have calculated the values for ADP1614 instead, which I am assuming will work fine for ADP1613. | |
Apr 21, 2014 at 13:16 | comment | added | tcrosley | @ValBlant My experience with other boost converters is that if Vin exceeds the Vout setpoint, then Vout will equal Vin (i.e. 5.1v in your case). I'm not sure about this one because of the diode D1. You could try modeling it using their simulator mentioned on page 13. It looks like the SEPIC configuration would also handle this situation and keep your output right at 5.0v, but it's not clear if you will still get the current you need with that circuit. Again, I suggest using their simulator. | |
Apr 21, 2014 at 7:52 | comment | added | Anindo Ghosh | That battery pack doesn't actually have plenty of capacity, as I've found from opening up several such power banks. The best ones in that size factor do not go much beyond 7600 mAh or beyond 1.4 Amperes current. The cheaper ones (< $30) are around 3000 mAh and 0.5 Amperes. | |
Apr 21, 2014 at 7:41 | comment | added | Val Blant | Would I need to configure the regulator as a "SEPIC Converter", as shown on page 22? | |
Apr 21, 2014 at 7:16 | comment | added | Val Blant | Thank you! This is what I was looking for. With a boost regulator like this, is it ok for Vin to exceed Vout? My battery outputs 5.1V before the large load is turned on. I can't find any data in the datasheet on how the regulator will handle this condition. | |
Apr 21, 2014 at 7:08 | history | answered | tcrosley | CC BY-SA 3.0 |