Timeline for Initial states in a digital system with more than one stable state
Current License: CC BY-SA 2.5
5 events
when toggle format | what | by | license | comment | |
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Mar 18, 2011 at 18:18 | comment | added | BarsMonster | Yes, BOD = brown-out detection. With slowly rising power (microseconds) pulse after capacitor would not be powerful enough to trigger your circuit. | |
Mar 18, 2011 at 16:59 | comment | added | Joe Mac | Implementing a detection scheme like that seems to be a little too complicated for my purposes. Maybe I'll just take the pullup resistor power hit. | |
Mar 18, 2011 at 16:25 | comment | added | Adam Lawrence | I think he's talking about brown-out detection. The initial state(s) would be held until the supply voltage reaches a minimum level (or is above a level for a certain period of time) then the initial state(s) are released. | |
Mar 18, 2011 at 16:09 | comment | added | Joe Mac | (2) Are you saying that a capacitor scheme will likely NOT work with a slow-rise of power? (3) Can you explain or link to an explanation of "BOD"? (4) Are you saying that 0V is the default state when powering up? | |
Mar 18, 2011 at 15:56 | history | answered | BarsMonster | CC BY-SA 2.5 |