Timeline for How do I keep my constant current source constant?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 1, 2017 at 12:02 | comment | added | Prasan Dutt | If 1v is supplied for voltage divider, then voltage at noninverting terminal of op-amp = (1k/2k)*1V = 0.5V = 500mV ... Considering Ideal op-amp voltage at inverting terminal will also be 500mV ... Current passing through emitter resistor = 500mV/5 = 100mA | |
| Jul 31, 2014 at 15:41 | vote | accept | MrPhooky | ||
| Jul 31, 2014 at 8:50 | vote | accept | MrPhooky | ||
| Jul 31, 2014 at 15:41 | |||||
| Jul 31, 2014 at 8:50 | comment | added | MrPhooky | Hey, so I implemented this circuit and it works really well so thank you so much for that, but I was just wondering if you could provide a link with more theory behind this circuit so I can try to understand what is happening more and how I would go about calculating any values if I wanted to change the current! | |
| Jul 30, 2014 at 13:39 | history | answered | Spehro 'speff' Pefhany | CC BY-SA 3.0 |