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new TeX delimiter, added link to datasheet
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stevenvh
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You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to rectify, smooth and regulate your 12$V_{ac}$12\$V_{AC}\$ transformer output to 5$V_{dc}$5\$V_{DC}\$.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12$V_{ac}$12\$V_{AC}\$ (rmsRMS).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12$V_{ac}$12\$V_{AC}\$ to 17$V_{dc}$15\$V_{DC}\$. The voltage is $\sqrt{2}$\$\sqrt{2}\$ times minus two diode voltage drops higher than the input voltage because the rectifier output is the peak AC voltage, not the rmsRMS AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805LM7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5$V_{dc}$5\$V_{DC}\$ your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to rectify, smooth and regulate your 12$V_{ac}$ transformer output to 5$V_{dc}$.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12$V_{ac}$ (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12$V_{ac}$ to 17$V_{dc}$. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5$V_{dc}$ your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to rectify, smooth and regulate your 12\$V_{AC}\$ transformer output to 5\$V_{DC}\$.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12\$V_{AC}\$ (RMS).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12\$V_{AC}\$ to 15\$V_{DC}\$. The voltage is \$\sqrt{2}\$ times minus two diode voltage drops higher than the input voltage because the rectifier output is the peak AC voltage, not the RMS AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The LM7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5\$V_{DC}\$ your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.
Fixed another rms calculation error.
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BG100
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You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to convert your new 12vAC to 12vDCrectify, and then you need to smooth and regulate ityour 12$V_{ac}$ transformer output to 5$V_{dc}$.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12vAC12$V_{ac}$ (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12vAC12$V_{ac}$ to 17vDC17$V_{dc}$. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5v5$V_{dc}$ your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to convert your new 12vAC to 12vDC, and then you need to smooth and regulate it.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12vAC (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12vAC to 17vDC. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5v your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to rectify, smooth and regulate your 12$V_{ac}$ transformer output to 5$V_{dc}$.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12$V_{ac}$ (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12$V_{ac}$ to 17$V_{dc}$. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5$V_{dc}$ your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.
Changed 1.414 to $\sqrt{2}$
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BG100
  • 5.8k
  • 4
  • 36
  • 48

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to convert your new 12vAC to 12vDC, and then you need to smooth and regulate it.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12vAC (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12vAC to 12vDC17vDC. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5v your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to convert your new 12vAC to 12vDC, and then you need to smooth and regulate it.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12vAC.
  2. The Diode Bridge (known as a bridge rectifier) will convert 12vAC to 12vDC.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5v your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.

You are correct. The transformer will only reduce the voltage (and increase the available current), so you need to add additional circuitry to convert your new 12vAC to 12vDC, and then you need to smooth and regulate it.

This is the type of circuit you should be looking to build:

AC to DC PSU

  1. The transformer reduces the voltage from mains to 12vAC (rms).
  2. The Diode Bridge (known as a bridge rectifier) will convert 12vAC to 17vDC. The voltage is $\sqrt{2}$ times higher than the input voltage because the rectifier output is the peak AC voltage, not the rms AC voltage.
  3. The first capacitor will smooth out the ripples that come from the output of the AC to DC bridge rectifier.
  4. The 7805 regulator will maintain a constant voltage as the load varies. For example if you are switching a light bulb on and off, the current will go up and down, and if you didn't have a regulator then the voltage would drop as the bulb is switched on. The regulator keeps it at the 5v your microcontroller needs.
  5. The final small capacitor filters out any noise or interference on the regulated side of the circuit.
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BG100
  • 5.8k
  • 4
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  • 48
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