ThisThe circuit diagram below is given in my book ( writtenwritten by Coughlin and Driscoll ) .
simulate this circuit – Schematic created using CircuitLab Here
Here it is said that, at thisthe condition when \$ E_d=+2V\$, the output voltage will be \$V_o=+5V\$ . But for an op amp, when the non inverting-inverting voltage is higher than then inverting voltage , the output voltage will be \$+V_{sat}\$, which is approximately +15V .
Why is the output for this Op Amp IC (LM339) is +5 volt ???Volts?
This circuit diagram below is given in my book ( written by Coughlin and Driscoll ) .
simulate this circuit – Schematic created using CircuitLab Here it is said that at this condition when \$ E_d=+2V\$ output voltage \$V_o=+5V\$ . But for op amp when the non inverting voltage is higher then inverting voltage , output voltage will be \$+V_{sat}\$ which is approximately +15V .
Why output for this Op Amp IC (LM339) is +5 volt ????
The circuit diagram below is given in my book (written by Coughlin and Driscoll).
simulate this circuit – Schematic created using CircuitLab
Here it is said that, at the condition when \$ E_d=+2V\$, the output voltage will be \$V_o=+5V\$. But for an op amp, when the non-inverting voltage is higher than then inverting voltage, the output voltage will be \$+V_{sat}\$, which is approximately +15V.
Why is the output for this Op Amp IC (LM339) +5 Volts?
This circuit diagram below is given in my book ( written by Coughlin and Driscoll ) .
simulate this circuit – Schematic created using CircuitLab Here it is said that at this condition when \$ E_d=+2V\$ output voltage \$V_o=+5V\$ . But for op amp when the non inverting voltage is higher then inverting voltage , output voltage will be \$+V_{sat}\$ which is approximately +15V .
Why output for this Op Amp IC (LM339) is +5 volt ????
