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Poles are the values of "s" that make the denominator zero. In both expressions you get that.

  1. s+3=0; s=-3; s+2=0; s=-2;

  2. s/3+1=0; s/3=-1; s=-3; s/2+1=0; s/2=-1; s=-2;

In the second link I can't find anything that suggests the opposite. What it does is to show how to draw an asymptotic bode plot.

In the expression |H(s)|=A ... it does say that p0, p1, p2... are the pole values, but pole values would be -p0, -p1, -p2 and so on.

Poles are the values of "s" that make the denominator zero. In both expressions you get that.

  1. s+3=0; s=-3; s+2=0; s=-2;

  2. s/3+1=0; s/3=-1; s=-3; s/2+1=0; s/2=-1; s=-2;

In the second link I can't find anything that suggests the opposite. What it does is to show how to draw an asymptotic bode plot.

Poles are the values of "s" that make the denominator zero. In both expressions you get that.

  1. s+3=0; s=-3; s+2=0; s=-2;

  2. s/3+1=0; s/3=-1; s=-3; s/2+1=0; s/2=-1; s=-2;

In the second link I can't find anything that suggests the opposite. What it does is to show how to draw an asymptotic bode plot.

In the expression |H(s)|=A ... it does say that p0, p1, p2... are the pole values, but pole values would be -p0, -p1, -p2 and so on.

Source Link

Poles are the values of "s" that make the denominator zero. In both expressions you get that.

  1. s+3=0; s=-3; s+2=0; s=-2;

  2. s/3+1=0; s/3=-1; s=-3; s/2+1=0; s/2=-1; s=-2;

In the second link I can't find anything that suggests the opposite. What it does is to show how to draw an asymptotic bode plot.