Timeline for how does ohms law apply in power system
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Nov 10, 2014 at 9:04 | comment | added | Douwe66 | If you connect the bulbs in series, they will not use the number of watts that they specifiy. Because the voltage is not the same. Say you connect two bulbs in series, they will both use half the voltage and thus emit less light. If you use two bulbs in series you will use less power than with a single bulb (assumed the resistance stays the smae for different voltages), because P = U^2/R. For a single bulb you get P=U^2/R and for 2 in series you get P=U^2/(2R). | |
| Nov 10, 2014 at 8:40 | comment | added | Gagandiep Singh | the energy meters in our houses are driven by the current flowing in our phase as per my knowledge. Greater the current greater is our consumption and the bill. Now if I connect one bulb one day, and on another day I put many bulbs(say in series) in the circuit, then which day my consumption would be greater? | |
| Nov 10, 2014 at 8:27 | comment | added | Gagandiep Singh | Ok that is right about the resistance of a thicker conductor being lesser. But thats not the point Im confused at. Consider any resistance element in the circuit. If more of such resistances are added in series then the current would increase or decrease? | |
| Nov 10, 2014 at 7:24 | history | answered | Douwe66 | CC BY-SA 3.0 |