Timeline for How to connect large traces to pads in PCB?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 29, 2014 at 7:11 | comment | added | Guill | @Matt Young I would agree that I am giving a simple answer. But simple does not mean it is not true. If you look at the equations involved (I = E/R, R = k/A, A = h x w) you obtain I = Kw/h. Which shows that the current capability of the trace is directly proportional to the width of the trace! | |
| Nov 29, 2014 at 5:32 | comment | added | Matt Young | -1 for a bunch of reasons, but "the current carrying capability of a trace is only as good as its thinnest section" is not true. This view is too simplistic for the real world of high current PCB design. | |
| Nov 29, 2014 at 4:59 | history | answered | Guill | CC BY-SA 3.0 |