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Majenko
Majenko
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Yes, you could just use a simple voltage divider. However, if you wanted to do it in a more fancy way with the 3.0V supply, you could use a simple resistor and transistor (NPMNPN or N-channel logic level MOSFET) arrangement which inverts the pin so it becomes active low:

schematic

simulate this circuit – Schematic created using CircuitLab

So to activate your enable pin you would output a logic LOW, and to disable it a logic HIGH. It then also becomes the same as most other "Chip Enable" pins which are active low.

Yes, you could just use a simple voltage divider. However, if you wanted to do it in a more fancy way with the 3.0V supply, you could use a simple resistor and transistor (NPM or N-channel logic level MOSFET) arrangement which inverts the pin so it becomes active low:

schematic

simulate this circuit – Schematic created using CircuitLab

So to activate your enable pin you would output a logic LOW, and to disable it a logic HIGH. It then also becomes the same as most other "Chip Enable" pins which are active low.

Yes, you could just use a simple voltage divider. However, if you wanted to do it in a more fancy way with the 3.0V supply, you could use a simple resistor and transistor (NPN or N-channel logic level MOSFET) arrangement which inverts the pin so it becomes active low:

schematic

simulate this circuit – Schematic created using CircuitLab

So to activate your enable pin you would output a logic LOW, and to disable it a logic HIGH. It then also becomes the same as most other "Chip Enable" pins which are active low.

Source Link
Majenko
Majenko
  • 56.4k
  • 9
  • 106
  • 190

Yes, you could just use a simple voltage divider. However, if you wanted to do it in a more fancy way with the 3.0V supply, you could use a simple resistor and transistor (NPM or N-channel logic level MOSFET) arrangement which inverts the pin so it becomes active low:

schematic

simulate this circuit – Schematic created using CircuitLab

So to activate your enable pin you would output a logic LOW, and to disable it a logic HIGH. It then also becomes the same as most other "Chip Enable" pins which are active low.