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Apr 13, 2017 at 12:32 history edited CommunityBot
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Mar 31, 2015 at 1:43 vote accept kolosy
Mar 30, 2015 at 16:03 comment added KyranF Then put a 10k resistor from the gate of the PFET to the 3.6V line, and when the "external input" pulls the gate down to 0V, the PFET will turn on. When the external input lets go/drives high, the resistor will make sure it turns off the PFET.
Mar 30, 2015 at 15:42 comment added Russell McMahon See additions to my answer. | What happens if yu just drive S1 from the input line? | What is the input voltage swing? | It is a very good idea to present all relevant data such as voltage levels etc in the question as referring to prior questions is OK for background within reason but hard if it is needed to get basic circuit conditions. We need to know vin voltage swing and current capability anmd ...
Mar 30, 2015 at 2:40 comment added kolosy @KyranF I grabbed the cheapest / first part I could that had the right Vgs. Not a high-frequency thing, so I don't really care about the rest of the parameters (right?). The scenario you describe is what I'm looking for.
Mar 28, 2015 at 7:30 answer added Russell McMahon timeline score: 0
Mar 28, 2015 at 5:21 comment added KyranF also, 55 microamps is probably just the leakage current.
Mar 28, 2015 at 5:20 comment added KyranF well, you've got a ridiculously high resistance "on" MOSFET, with crazy over-the-top 200V rating. But hey, at least it will turn on with only 1.4-2V Vgs. Have you got a resistor pulling up the gate of the FET? If the "external input" goes low, it will turn on the PFET. If the external input goes high, it will turn the PFET off, as long as it's going higher than or equal to 3.6V
Mar 28, 2015 at 4:25 history asked kolosy CC BY-SA 3.0